Does weight affect an object's speed during free fall?

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SUMMARY

In a vacuum, all objects fall at the same speed regardless of their weight, as demonstrated by the example of a feather and a bowling ball dropped on the moon. The weight of an object, defined as the force acting on it due to gravity (Weight = Mass x Acceleration due to gravity), does not affect the acceleration during free fall. According to Newton's second law, while the force of gravity is greater on heavier objects, their acceleration remains constant at 9.81 m/s². Terminal velocity, influenced by air resistance, differs between objects but is irrelevant in a vacuum.

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  • Understanding of Newton's second law of motion
  • Basic knowledge of gravitational force and weight
  • Familiarity with the concept of terminal velocity
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musicboy
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Hi there
Just wondering: all objects fall at the same speed, right(not taking into account air resistance)? So if I dropped a feather and a bowling ball on the moon, they'd fall at the same speed. So far so good.
But my physics book's definition of weight is "The weight of an object is the force that acts on it because of gravity; Weight = Mass x Acceleration due to gravity" .
The bowling ball's mass is clearly greater than the feather's, so therefore it's weight and therefore pull of gravity on it must be different, resulting in a different speed...
Confused!
Any help much appreciated :)
 
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hi musicboy! :smile:
musicboy said:
… my physics book's definition of weight is "The weight of an object is the force that acts on it because of gravity; Weight = Mass x Acceleration due to gravity" .
The bowling ball's mass is clearly greater than the feather's, so therefore it's weight and therefore pull of gravity on it must be different, resulting in a different speed...

yes, the force of gravity on it is greater (Mg > mg)

but force = mass times acceleration (that's Newton's second law),

so the accelerations are the same (A = Mg/M, a = mg/m) :wink:
 
musicboy said:
Weight = Mass x Acceleration...

The bowling ball's mass is clearly greater than the feather's, so therefore it's weight and therefore pull of gravity on it must be different,
You have the equation right there. If you change Weight & Mass by the same factor, Acceleration stays the same.

musicboy said:
resulting in a different speed...
The terminal speed, where air resistance = weight, is different. But in vacuum they fall the same.
 
To add to what A.T. And Tiny-Tim have said... There's an FAQ on this at https://www.physicsforums.com/forumdisplay.php?f=209
 
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Gotcha :)
Thanks very much all of you for quick and concise replies.
Have a good day :D
 

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