Free R-Module Basics: What is a Copy of R?

  • Context: Graduate 
  • Thread starter Thread starter Artusartos
  • Start date Start date
Click For Summary
SUMMARY

A free R-module is defined as a left R-module F that is isomorphic to a direct sum of copies of R, as stated in the textbook. This can be expressed mathematically as F ≅ ∏α∈JRα, indicating that the underlying structure resembles an abelian group similar to vector spaces. The discussion highlights that each coordinate in the basis, such as (1,0,...,0) and (0,1,0,...,0), corresponds to individual copies of R, reinforcing the concept that a left R-module with a basis qualifies as a free module.

PREREQUISITES
  • Understanding of R-modules and their definitions
  • Familiarity with concepts of isomorphism in algebra
  • Knowledge of direct sums and products in module theory
  • Basic grasp of vector spaces and their properties
NEXT STEPS
  • Study the properties of free R-modules in detail
  • Explore the relationship between bases and free modules in algebra
  • Learn about isomorphisms and their applications in module theory
  • Investigate the implications of direct sums and products in R-modules
USEFUL FOR

Mathematicians, algebraists, and students studying module theory or abstract algebra, particularly those interested in the structure and properties of R-modules.

Artusartos
Messages
236
Reaction score
0
From my textbook:

A free R-module is "A left R-module F is called a free left R-module if F is isomorphic to a direct sum of copies of R..."

I know that another definition of an R-module a module with a basis...but I don't know how to connect that definition with this one. Also, what does "copies of R" mean?

Thanks in advance
 
Last edited:
Physics news on Phys.org
Artusartos said:
From my textbook:

A free R-module is "A left R-module F is called a free left R-module if F is isomorphic to a direct sum of copies of R..."

Can we think of it as
$$F\cong\prod_{\alpha\in J}R_\alpha$$
This is the underlying abelian group (analogous to vectors in vector space), and it looks like there is a natural way to multiply on the left by elements of R (analogous to scalars in a vector space).

I know that another definition of an R-module a module with a basis...but I don't know how to connect that definition with this one.

For F above, a basis could be elements like (1,0,...,0), (0,1,0,...,0) and so on. Notice each coordinate alone looks like R.

So that seems to suggest that a left R-module does indeed have a basis. Now let's consider if we think a left R-module with a basis is a free module. Uh, never mind, I'll leave that for someone else
Also, what does "copies of R" mean?

The product above consists of copies of R.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 12 ·
Replies
12
Views
771
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K