Freefall with constant velocity

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SUMMARY

The discussion centers on the physics of an object released from a helicopter moving at constant velocity. Participants confirm that, assuming no air resistance, the object will always be directly below the helicopter until it impacts the ground. This means that the horizontal distance between the helicopter and the target (in this case, a truck) will be zero at the moment of impact. The conclusion is that the object's trajectory is directly influenced by the helicopter's constant horizontal motion.

PREREQUISITES
  • Understanding of Newtonian physics principles
  • Knowledge of projectile motion
  • Familiarity with concepts of constant velocity
  • Basic grasp of air resistance effects on falling objects
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  • Study the principles of projectile motion in detail
  • Learn about the effects of air resistance on falling objects
  • Explore the concept of point mass in physics
  • Investigate real-world applications of constant velocity in physics problems
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Femme_physics
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(not a homework question, just something I thought about)

http://img23.imageshack.us/img23/1130/hellhell.jpg


So, if I'm told that the helicopter here let's go of an object and he wants the object to hit the truck. (all objects are "point mass"). Can I say right from the get go that, as long as there is constant velocity, the moment where the object hits the truck is exactly where the horizontal distance between the helicopter and the truck is zero. Correct?
 
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Hi Femme_physics! :wink:

Yes, the falling object (if we ignore air resistance) is immediately below the helicopter at all times. :smile:
 
Yay!

Tiny-tim! :D So glad to see you replying to me again! *hugs!* and thanks!

And glad that I'm right :)
 

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