Frequency difference to find a 20m whale

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SUMMARY

The discussion focuses on determining the sonar frequency required to detect a 20-meter whale using coherent sound waves from two boats. The key formula derived is for the maximum displacement, given by y_{max} = \frac{d \lambda (n+\frac{\phi}{2\pi})}{a}, where d is the depth of the whale (350m), B=2.18\times 10^{9} Pa, and \rho =1.05 \times 10^{3} kg. The phase velocity of the sonar waves is calculated using v_{p}=\sqrt{\frac{B}{\rho}}. The discussion emphasizes the importance of ensuring the whale occupies a maximum of the radiation pattern for reliable detection.

PREREQUISITES
  • Understanding of wave interference principles, specifically double slit experiments.
  • Familiarity with sonar technology and its applications in marine biology.
  • Knowledge of fluid mechanics, particularly the concepts of pressure and density.
  • Basic algebra and calculus for manipulating equations and solving for variables.
NEXT STEPS
  • Research the principles of wave interference and how they apply to sonar detection.
  • Learn about the mathematical modeling of sound waves in different mediums.
  • Explore the effects of phase differences in coherent wave sources on detection accuracy.
  • Investigate sonar frequency selection techniques for optimal marine animal detection.
USEFUL FOR

Marine biologists, acoustic engineers, and researchers involved in underwater detection systems will benefit from this discussion, particularly those focused on optimizing sonar technology for detecting large marine animals like whales.

bananabandana
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Homework Statement


Please see attachment for diagram. The two boats are coherent sources of sound waves (phase difference ## \phi##) - i.e it's a double slit problem.
upload_2015-4-6_15-24-55.png

Prove the formula given for ## y_{max}##.
Suppose the whale is 20m long. How large should the sonar frequency ##f## be so that the whale can always be detected? Assume ## B=2.18\times 10^{9} Pa ## and ## \rho =1.05 \times 10^{3} \ kg ##

Homework Equations


$$ y_{max} = \frac{d \lambda (n+\frac{\phi}{2\pi})}{a} $$
Where ## y_{max}## is the ##y## value at which the two sources constructively interfere for a given depth, ##d##. The depth of the whale (the tube shaped thing) is ## d=350m##.

The phase velocity of the sonar waves, ## v_{p}## is given by:
$$ v_{p}=\sqrt{\frac{B}{\rho}} $$

The Attempt at a Solution


Is it sensible just to substitute ##y_{max}=20## and just do the algebra? ( I have already done the proof for ##y_{max}##.)This would seem the obvious thing to do from the diagram ( and since the question is only a couple of marks). But I'm just wondering if this would really work. It says earlier in the question that the whale is moving horizontally - so I'm just thinking there might be a more complete way to approach the problem, but I don't know how to do it...
 
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bananabandana said:

Homework Statement


Please see attachment for diagram. The two boats are coherent sources of sound waves (phase difference ## \phi##) - i.e it's a double slit problem.
View attachment 81564
Prove the formula given for ## y_{max}##.
Suppose the whale is 20m long. How large should the sonar frequency ##f## be so that the whale can always be detected? Assume ## B=2.18\times 10^{9} Pa ## and ## \rho =1.05 \times 10^{3} \ kg ##

Homework Equations


$$ y_{max} = \frac{d \lambda (n+\frac{\phi}{2\pi})}{a} $$
Where ## y_{max}## is the ##y## value at which the two sources constructively interfere for a given depth, ##d##. The depth of the whale (the tube shaped thing) is ## d=350m##.

The phase velocity of the sonar waves, ## v_{p}## is given by:
$$ v_{p}=\sqrt{\frac{B}{\rho}} $$

The Attempt at a Solution


Is it sensible just to substitute ##y_{max}=20## and just do the algebra? ( I have already done the proof for ##y_{max}##.)This would seem the obvious thing to do from the diagram ( and since the question is only a couple of marks). But I'm just wondering if this would really work. It says earlier in the question that the whale is moving horizontally - so I'm just thinking there might be a more complete way to approach the problem, but I don't know how to do it...
To locate the whale reliably, I suppose it must occupy one maximum of the radiation pattern. If it occupies more, its direction will be uncertain. If less, the return signal will be smaller than necessary. Notice that if the whale lies symmetrically across a pattern null, that will still be a null. The "head" will reflect one lobe and the "tail" the adjacent one, and adjacent lobes are in antiphase.
 

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