Frequency of damped mass-spring system

Click For Summary
SUMMARY

The discussion focuses on calculating the frequency of oscillation for a damped mass-spring system involving a rodent of mass 0.307 kg and a spring with a force constant of 2.48 N/m. The damping coefficient b is given as 0.894 kg/s. The calculated angular frequency (ω) is 0.452 rad/s, and the user seeks assistance in determining the critical damping condition for the system. The discussion emphasizes the importance of free body diagrams and differential equations in analyzing the motion of the mass under the influence of multiple forces.

PREREQUISITES
  • Understanding of mass-spring systems and Hooke's Law
  • Knowledge of damping forces and their effects on oscillation
  • Familiarity with angular frequency calculations
  • Ability to solve differential equations related to motion
NEXT STEPS
  • Learn about critically damped systems and the conditions for critical damping
  • Study the derivation of the differential equation for damped harmonic motion
  • Explore the effects of varying the damping coefficient on oscillation behavior
  • Investigate the use of free body diagrams in analyzing dynamic systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to clarify concepts related to damped systems.

Adel A
Messages
5
Reaction score
0
[Mentor's note: Thread title changed to reflect question content]

I really need some help with this one:

1. Homework Statement

An unhappy rodent of mass 0.307kg , moving on the end of a spring with force constant 2.48N/m , is acted on by a damping force Fx=−b⋅vx.

Part A
If the constant b has the value 0.894kg/s , what is the frequency of oscillation of the mouse?

Part B
For what value of the constant b will the motion be critically damped?

Homework Equations


F = -kx
F = mg
f = 1/T = ω/2π

The Attempt at a Solution


Part A:
Fx = -bvx = -0.894⋅vx
-kx = F => m⋅a = -k⋅x, and I put the numbers in and got:
0.307⋅9.81 = -2.48⋅x => x = -1.214 m

ω = sqrt(k/m), and I put the numbers in and got: ω = 0.452 rad/s

Then I tried to calculate vx by:

vx⋅(-0.894)=3.0117 => vx = -3.369 m/s

I don't know what to do. Thankful for all help I can get!
 
Last edited by a moderator:
Physics news on Phys.org
I guess the rodent is hanging from the ceiling (attached to the spring which has its other end attached to the ceiling). How far above or below equilibrium position does it start?

Also, the solutions for v(x) and F(x) are not going to be numbers (since they change with time).

Finally, if multiple forces are acting on an object F = F1 + F2 + F3. You have the gravitational force, the force from the spring and the damping force all acting on the rodent at the same time. I recommend drawing the system with all forces. It may make things easier.
 
I would start of with drawing a free body diagram, then you should be able to set up a differentialequation describing the motion of the mass.
Depending on the value of the constant b, you will be able to get different soultions to this equation, descirbing different kinds of damping. :)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
17
Views
3K
Replies
3
Views
842
  • · Replies 11 ·
Replies
11
Views
3K
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
17
Views
2K
Replies
13
Views
2K
Replies
6
Views
4K
Replies
3
Views
987
  • · Replies 14 ·
Replies
14
Views
2K