Frequency of oscillation (in Hz) question help Thanks

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SUMMARY

The discussion centers on calculating the frequency of oscillation for a wooden raft after a 75 kg man steps off. The force constant was correctly identified as 21,000 Nm. The frequency of oscillation was calculated using the formula f = (1/2π)√(k/m), resulting in a frequency of approximately 0.776 Hz. The approach of modeling the raft's behavior as a mass-spring system was validated by participants, confirming the appropriateness of the method.

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Homework Statement



A 320 kg wooden raft floats on a lake in equilibrium. When a 75 kg man steps carefully onto the raft, it floats 3.5 cm deeper into the water. When he steps off, the raft oscillates for a while.

I figured out that the force constant is 21,000 Nm - first off, is that correct?

Now my QUESTION is, calculate the Frequency of oscillation (in Hz) after the man steps off the raft?


Homework Equations





The Attempt at a Solution



I came up with...

2pi sqrt (m/k)

2pi sqrt (320/21,000) = .776 Hrtz
 
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I see you used the spring equation F = kx and found the k (agree with 21000).
I have some reservations about treating this situation like a spring, but it makes considerable sense and I can't think of an alternative. Anyway, continuing with the spring model, you would use
T = 2pi sqrt (m/k)
to find the period and then the frequency.
 
Your reasoning is more important than your results.

Treated like a mass on a spring?
(75x9.8)N was enough for 3.5cm extension is 21000Nm - well done.
You plugged that into the equation for period of a mass on a spring :(

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}=\frac{1}{T}
 

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