# Frequency of a simple harmonic oscillator

In summary, the question asks for the characteristic frequency of a simple harmonic oscillator with a mass of 1 kg and a spring constant of 10 N/m. The relevant equations are Hooke's law (F=-ky) and \omega^{2} = K/M, and the characteristic frequency can be found by solving for \omega = 2 \cdot \pi \cdot f. Some guidance and resources, such as the textbook and class notes, can help with finding the solution.

## Homework Statement

Consider a mass hanging from an ideal spring. Assume the mass is equal to 1 kg and the spring constant is 10 N/m. What is the characteristic frequency of this simple harmonic oscillator?

## Homework Equations

No idea I think Hookes law
F=-ky
Some other relevant equations?
$\omega^{2}$ = K/M

## The Attempt at a Solution

No idea where to start. Some guidance on steps would be helpful! thanks

Also note that $\omega = 2 \cdot \pi \cdot f$. You now have all the tools, just solve!

## Homework Statement

Consider a mass hanging from an ideal spring. Assume the mass is equal to 1 kg and the spring constant is 10 N/m. What is the characteristic frequency of this simple harmonic oscillator?

## Homework Equations

No idea I think Hookes law
F=-ky
Some other relevant equations?
$\omega^{2}$ = K/M

## The Attempt at a Solution

No idea where to start. Some guidance on steps would be helpful! thanks

You must show some effort before we can be of much tutorial help. Look at your textbook and class notes -- they should contain the material about spring-mass oscillation. You can also look at this wikipedia page:

http://en.wikipedia.org/wiki/Simple_harmonic_motion

## 1. What is a simple harmonic oscillator?

A simple harmonic oscillator is a system or object that moves back and forth between two points in a regular and predictable manner. It follows the principles of harmonic motion, where the force acting on the object is directly proportional to its displacement from its equilibrium position.

## 2. How is the frequency of a simple harmonic oscillator calculated?

The frequency of a simple harmonic oscillator is calculated using the equation f = 1/(2π√(k/m)), where f is the frequency in hertz (Hz), k is the spring constant of the oscillator, and m is the mass of the object attached to the spring.

## 3. What factors affect the frequency of a simple harmonic oscillator?

The frequency of a simple harmonic oscillator is affected by the mass of the object attached to the spring, the spring constant of the oscillator, and the amplitude of the oscillation. It is also influenced by external factors such as friction and air resistance.

## 4. How does the frequency of a simple harmonic oscillator change with increasing mass?

As the mass of the object attached to the spring increases, the frequency of the simple harmonic oscillator decreases. This is because a heavier object requires a greater force to achieve the same amplitude of oscillation, resulting in a lower frequency.

## 5. Can the frequency of a simple harmonic oscillator be changed?

Yes, the frequency of a simple harmonic oscillator can be changed by altering its mass, spring constant, or amplitude of oscillation. External factors such as friction and air resistance can also affect the frequency. Additionally, changing the length of the spring or the gravitational pull can also impact the frequency of the oscillator.

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