The characteristic frequency of a simple harmonic oscillator can be calculated using the formula \(\omega^{2} = \frac{K}{M}\), where \(K\) is the spring constant and \(M\) is the mass. In this case, with a mass of 1 kg and a spring constant of 10 N/m, the frequency can be determined by first calculating \(\omega\) and then converting it to frequency \(f\) using the relation \(\omega = 2 \cdot \pi \cdot f\). The discussion emphasizes the importance of referring to textbooks and class notes for foundational concepts related to spring-mass oscillation.
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AdrianHudson said:Homework Statement
Consider a mass hanging from an ideal spring. Assume the mass is equal to 1 kg and the spring constant is 10 N/m. What is the characteristic frequency of this simple harmonic oscillator?
Homework Equations
No idea I think Hookes law
F=-ky
Some other relevant equations?
\omega^{2} = K/M
The Attempt at a Solution
No idea where to start. Some guidance on steps would be helpful! thanks