- #1
LaLaLina
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Homework Statement
A mass m = 2.0 kg is attached to a spring having a force constant k = 990 N/m as in the figure. The mass is displaced from its equilibrium position and released. Its frequency of oscillation (in Hz) is approximately _____ . [/B]
Homework Equations
[itex] \omega=\sqrt\frac{k}{m} [/itex]
[itex] T=\frac{2\pi}{\omega} [/itex] [itex] f=\frac{\omega}{2\pi} [/itex]
[/B]
The Attempt at a Solution
m= 2.0 kg
k= 990 N/m
f = ?
omega = sqrt((990N/m)/(2.0kg)) = 22.25 rad/s
f= (22.25 rad/s)/(2pi) = 3.5 Hz
The answer to the problem, is 4.0 Hz. However, I don't believe I should have rounded up. I believe I have made an error in how to solve the problem.
Have I gone wrong in choosing the formulas to use? or
Should I have taken something else into account based on the mention of the equilibrium statement? and if so, what does that imply?
I recall doing another type of spring problem where it went past its point of equilibrium, but we were using velocity and its angle and solving for v using
dy/dt = -A(omega)sin(omega(t)+phi), however I was reviewing the slides before this problem, and it doesn't seem to address the equilibrium.
I thank you for your assistance very much. I'm studying for my final on Monday and I'm trying to be prepared.[/B]