1. The problem statement, all variables and given/known data Assume that there is a tank on a 200 ft pedestal type support. When full the tank and contents have a weight of 50,000 lbs and it is never drained to a point where the tank and contents have a weight less than 20,000 lbs. Assume the pedestal weight is negligible compared to the tank's weight and that the dimensions of the tank are such that it might be assumed a lumped mass( a particle). A force transducer is attached to a truck, is connected by a 600ft long cable to the tank, such that there is an 18° angle relative to the horizontal, and that the cable's line of action passes roughly through the centroid of the tank and its contents. Careful measurements indicate that the deflection of the tank is proportional to the force and that the tank has moved horizontally 20.5 plus or minus 0.04 inches when the force in the cable is 5000 lbs. a) Estimate the natural frequency for vibration of the tank at both its maximum and minimum weights. In other words at 50,000 lbs and 20,000 lbs. b) Estimate the frequency range of horizontal earth motion which "would" likely cause the tank to displace 2 times or more than the magnitude of the "earth's horizontal vibrational motion". Neglect damping. 2. Relevant equations ω = 2π/P ƒ = 1/P ωn = √(k/n) Magnification Factor = 1/(1 - (ωƒ/ωn)^2) 3. The attempt at a solution I have some trouble with these kind of questions where I feel like there is a lot going on. I sometimes don't know where to start, so I apologize in advance if I ask dumb questions! Like I said, I'm not sure where to start, but I drew a free body diagram of the tank where there are only two forces acting on it. The forces on the water tank are its weight and T, the tension in the cable. I have that the force of T is 5000cos18 since the cable is at an 18 degree angle relative to the horizontal. From there I'm not quite sure where to go. If there's anyone out there that could help me, I would sure appreciate it. Again, these "vibration" problems always seem to be so difficult for me so a thousand "thank yous" in advance!