Thermodynamics problem -- Water pumped into an enclosed tank....

[danny12345]

Homework Statement

Q3.1 (a) A pump forces 1m^3 /min of water horizontally from an open well to a closed tank where the pressure is 0.9 Mpa.compute the work the pump must do upon the water in an hour just to force the water into the tank against the pressure.sketch the system upon which the work iss done before and after the process.

Homework Equations

The Attempt at a Solution

here flow rate is 1m^3/min
p1=0.101325 pa
p2=0.9 pa
we don't know v.
but equation formed will be as:
w=dpdv
now I'm where i can get v.

 

[haruspex]

This is not a thermodynamics question. Titling it so may have deterred some potential responders.
Where you wrote pa in your attempted solution, I guess you meant MPa.
You don't need to know the velocity.
I don't understand your w=dpdv equation. Please explain the terms.

 

[danny12345]

it's w=(p2-p1)(v2-v1)

 

[danny12345]

it's w=(p2-p1)(v2-v1)

 

[haruspex]

it's w=(p2-p1)(v2-v1)

I asked you to explain the terms. What are the v's? If they're velocities, and the p's are pressures, and w is work, then the equation is dimensionally wrong. If the v's are volumes then the dimensions work, but I don't see the relevance to problem. [And anyway, I think you would mean W= d(PV)=PdV+VdP.]

 

[danny12345]

v=volume

 

[haruspex]

v=volume

Ok.
You know the flow rate, and you know the time, so...

 

[danny12345]

so what then?

 

[haruspex]

so what then?

So you can find the volume.

 

[danny12345]

how?

 

[haruspex]

how?

A pump forces 1m^3 /min of water ... the work the pump must do upon the water in an hour...

A cubic metre of water per minute, for one hour, gives...?