A pyramid weighing 4000 lb has a base 6ft square and an altitude of 4ft. The base covers an opening in the floor of a tank in which there is water 4 ft deep. Underneath the floor of the tank and on the water surface there is air at atmospheric pressure. What vertical force is required to lift the pyramid off the floor?
Where F is the force; δ=specific weight of the liquid; V is volume
The Attempt at a Solution
I'm not really sure if I analyze what it should look like, but here is my attempt.
Fv is the force by the fluid against the pyramid
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