Fricition: Block on inclined plane

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SUMMARY

The discussion centers on calculating the maximum angle (theta) for a block of mass m on an inclined plane, given a coefficient of static friction of 0.30 and no external force (||P|| = 0). Participants suggest breaking down the gravitational force (mg) into its slope and normal components to simplify the problem. The key to solving this problem lies in understanding the balance of forces acting on the block, specifically the static friction and gravitational components.

PREREQUISITES
  • Understanding of static friction and its coefficient
  • Knowledge of force decomposition into components
  • Familiarity with Newton's laws of motion
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Study the principles of static friction and its role in inclined planes
  • Learn how to decompose forces into their components in physics problems
  • Explore Newton's laws of motion in the context of inclined planes
  • Practice solving problems involving angles and forces on inclines
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Students studying physics, particularly those focusing on mechanics and inclined plane problems, as well as educators looking for examples of static friction applications.

yellowsnow
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Homework Statement


What is the maximum angle (theta) for which the block of mass m in (figure) will not slide down the incline if the coefficient of static friction is 0.30 and ||P|| = 0?

Figure:

EB2.png


Homework Equations



I know this isn't a hard problem, but I just seem to be stuck on it.

The Attempt at a Solution



I started by replacing the force "P" with it's X and Y components, then adding the 2 forces to the block, "mg" and "N", the normal force.

After that I'm stumped. I'd appreciate if anyone can help me.
 
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Welcome to PF!

Hi yellowsnow! Welcome to PF! :smile:
yellowsnow said:
What is the maximum angle (theta) for which the block of mass m in (figure) will not slide down the incline if the coefficient of static friction is 0.30 and ||P|| = 0?
…
I started by replacing the force "P" with it's X and Y components, then adding the 2 forces to the block, "mg" and "N", the normal force.

(do you really mean ||P|| = 0 ?)

It's a lot easier if you replace g, by its slope and normal components :wink:
 

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