Friction and Acceleration in Inclined Surfaces

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SUMMARY

The discussion focuses on calculating the acceleration of two boxes being pulled on an inclined surface with friction. A force of 40 N is applied at an angle of 30 degrees to a system consisting of a 3.0 kg top box and a 6.0 kg bottom box, with a coefficient of kinetic friction of 0.20. The correct application of Newton's second law, F=ma, is emphasized, along with the need to account for the angle of the applied force and frictional forces. Additionally, the minimum coefficient of static friction required to prevent the smaller box from sliding on the larger box is also a key point of discussion.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Knowledge of friction coefficients, specifically static and kinetic friction
  • Ability to analyze forces on inclined planes
  • Familiarity with drawing and interpreting free-body diagrams
NEXT STEPS
  • Study the effects of inclined angles on force calculations in physics
  • Learn how to calculate static and kinetic friction coefficients in various scenarios
  • Explore advanced applications of Newton's laws in multi-body systems
  • Practice drawing and analyzing free-body diagrams for complex systems
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of forces acting on objects in motion, particularly in inclined scenarios.

runningirl
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Homework Statement



A person pulls with a force of 40 N on two boxes at rest. The top box is 3.0 kg and the bottom box is 6.0 kg. The coefficient of kinetic friction between the floor and the larger box is .20 and the angle is 30 degrees.

a) if the smaller box doesn't slide on top of the larger box, what is the acceleration of the larger box?

b) Given your answer to part a, what must be the minimum value of the coefficient of static friction between the smaller box and the larger box?


Homework Equations



f=ma
f=(coefficient)*(normal force

The Attempt at a Solution



40=9(a)?

a=40/9?

i'm not even sure if this is the answer for part a.
 
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While your formula, f=ma, is mostly correct, you have not applied it properly.

The fact that the force is applied at an angle changes the situation, and you need to reconsider how you calculate the force.
Also, why I said mostly correct is because you failed to include the sum F=ma. You need to consider the coefficient of friction when solving for acceleration.
A piece of advice is to draw a force diagram. That will help you see all the forces.

Hope that helps you get moving in the right direction!
 

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