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## Homework Statement

A uniform ladder with mass m

_{2}and length L rests against a smooth wall. A do-it-yourself enthusiast of mass m

_{1}stands on the ladder a distance d from the bottom (measured along the ladder). The ladder makes an angle x with the ground. There is no friction between the wall and the ladder, but there is a frictional force of magnitude f between the floor and the ladder. N

_{1}is the magnitude of the normal force exerted by the wall on the ladder, and N

_{2}is the magnitude of the normal force exerted by the ground on the ladder. Throughout the problem, consider counterclockwise torques to be positive. None of your answers should involve pi (i.e., simplify your trig functions).

Sum the torques given in the problem about the point at which the ladder touches the wall.

## Homework Equations

T(torque)=F*d

See attachment for diagram.

## The Attempt at a Solution

I know the answer is,

-m

_{1}g(L-d)cos(x)-(m

_{2}g)(L/2)(cos(x))-fLsin(x)+N

_{2}Lcos(x)

I know that torque is the force multiplied by the distance to the pivot point. What I don't get is why we are only concerned with with each force's vertical distance from the pivot point and not the horizontal distance. Help, please?