Friction at an angle verification

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The discussion focuses on calculating the maximum coefficient of friction for boxes sliding down a 30-degree ramp. The user determined the acceleration to be 0.99 m/s² using the distance and time provided. They applied the equation mgsinTHETA - umgcosTHETA = ma, leading to a coefficient of friction of approximately 0.46. Another participant confirmed the method without verifying the numbers. The user also requested assistance with a separate topic on tension and centripetal force.
warmfire540
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Hey, i just want to make sure I'm doing this right:

At the end of a factory production line, boxes start from rest and slide down a 30o ramp 5.4 m long. If the slide is to take no more than 3.3 s, what is the maximum coefficient of friction between the box and the slide?


I first found out the acceleration:
5.4=0.5a(3.3)^2
a=.99m/s^2
so i then did
mgsinTHETA-umgcosTHETA=ma (mass cancels out)
4.9-8.5u=0.99
-8.5u=-3.91
u=.46...the coefficent of friction, it seems to work..

however i still need help on my post "Tension and centripital force revisited"
THANKS for alll ya'lls help
 
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warmfire540 said:
Hey, i just want to make sure I'm doing this right:

At the end of a factory production line, boxes start from rest and slide down a 30o ramp 5.4 m long. If the slide is to take no more than 3.3 s, what is the maximum coefficient of friction between the box and the slide?I first found out the acceleration:
5.4=0.5a(3.3)^2
a=.99m/s^2
so i then did
mgsinTHETA-umgcosTHETA=ma (mass cancels out)
4.9-8.5u=0.99
-8.5u=-3.91
u=.46...the coefficent of friction, it seems to work..

however i still need help on my post "Tension and centripital force revisited"
THANKS for alll ya'lls help

I didn't check the numbers, but your method seems correct.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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