How Do You Calculate the Coefficient of Kinetic Friction on a Ramp?

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Homework Help Overview

The discussion revolves around calculating the coefficient of kinetic friction for a box sliding down a ramp inclined at 30°. The original poster expresses uncertainty about how to approach the problem, particularly in determining the forces involved and how to relate them to the coefficient of friction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the forces acting on the box, including gravity and friction, and how to resolve these forces into components. There are questions about applying Newton's second law and how to express forces in terms of mass and acceleration due to gravity. The original poster and others explore the relationships between these forces and the coefficient of kinetic friction.

Discussion Status

The discussion is ongoing, with participants actively engaging in clarifying concepts and exploring different interpretations of the forces involved. Some guidance has been provided regarding the relationships between the forces and how to express them symbolically, but no consensus or final solution has been reached.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is also a focus on maintaining symbolic representations rather than substituting numerical values at this stage.

  • #31
-cosθ x m x a / sinθ = Uk?
 
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  • #32
wait no negative
 
  • #33
maybe?
 
  • #34
ughschool said:
-cosθ x m x a / sinθ = Uk?

No.


This is your equation

-mgsinθ + mμkgcosθ = -ma

Solve for 'a'.
 
  • #35
gsinθ + μkgcosθ = a?
 
  • #36
ughschool said:
gsinθ - μkgcosθ = a?

This is what it should be. So solve for μk now.
 
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  • #37
gsinθ-a/-gcosθ=uk?
 
  • #38
ugh wait no sorry
gsinθ-a/gcosθ=uk?
 
  • #39
ahhhhhhh is it + or -?
 
  • #40
i think its -
 
  • #41
ughschool said:
ugh wait no sorry
gsinθ-a/gcosθ=uk?

This is correct. So just substitute your values.
 
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Likes   Reactions: 1 person

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