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Hey, i just want to make sure I'm doing this right:
At the end of a factory production line, boxes start from rest and slide down a 30o ramp 5.4 m long. If the slide is to take no more than 3.3 s, what is the maximum coefficient of friction between the box and the slide?
I first found out the acceleration:
5.4=0.5a(3.3)^2
a=.99m/s^2
so i then did
mgsinTHETA-umgcosTHETA=ma (mass cancels out)
4.9-8.5u=0.99
-8.5u=-3.91
u=.46...the coefficent of friction, it seems to work..
however i still need help on my post "Tension and centripital force revisited"
THANKS for alll ya'lls help
At the end of a factory production line, boxes start from rest and slide down a 30o ramp 5.4 m long. If the slide is to take no more than 3.3 s, what is the maximum coefficient of friction between the box and the slide?
I first found out the acceleration:
5.4=0.5a(3.3)^2
a=.99m/s^2
so i then did
mgsinTHETA-umgcosTHETA=ma (mass cancels out)
4.9-8.5u=0.99
-8.5u=-3.91
u=.46...the coefficent of friction, it seems to work..
however i still need help on my post "Tension and centripital force revisited"
THANKS for alll ya'lls help