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At the end of a factory production line, boxes start from rest and slide down a 30o ramp 5.4 m long. If the slide is to take no more than 3.3 s, what is the maximum coefficient of friction between the box and the slide?

I first found out the acceleration:

5.4=0.5a(3.3)^2

a=.99m/s^2

so i then did

mgsinTHETA-umgcosTHETA=ma (mass cancels out)

4.9-8.5u=0.99

-8.5u=-3.91

u=.46.....the coefficent of friction, it seems to work..

however i still need help on my post "Tension and centripital force revisited"

THANKS for alll ya'lls help