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Friction- related to banking of road

  1. Jan 1, 2010 #1
    1. The problem statement, all variables and given/known data

    a turn of radius 20m is banked for vehicles going at a speed of 10 m/s ( considering no friction). If the friction co-efficient between road and tyre is 0.3, then the minimum speed of the vehicle is 5x/(11.5)^1/2.


    2. Relevant equations

    in case of banking and no friction

    tan A= v^2/rg

    in case of banking and friction both,

    v=[rg(u + tan A)/(1 - u tanA)]^1/2



    3. The attempt at a solution



    well,
    i did not actually understand what the first statement means because if there is friction, then how can one avoid it?
     
  2. jcsd
  3. Jan 1, 2010 #2

    Doc Al

    User Avatar

    Staff: Mentor

    Re: Friction- related to baning of road

    This means that the banking angle of the road is just right so that a vehicle moving at 10 m/s requires no friction to make the turn. (Figure out the angle.)
     
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