A sled is pulled at a constant speed over a horizontal surface where the kinetic coefficient of friction is .20. What is the minimum force necessary to keep the sled moving if its mass is 2 slugs?
f(s)=U(s)N or f(s)=Ns(mg)
F(s)= Frictional Force
(Not sure about this equation or problem)
The Attempt at a Solution
F(s) = Ns(mg)
F(s) = (.20)(2 slugs)(32 ft/s^(2))
F(s) = 12.8 N ???
Am I doing this right or wrong? Can somebody please show me how to do this?