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**frictional talk -- mass suspended from a flywheel**

## Homework Statement

a mass of 0.5kg is suspended from a flywheel. if the mass is released from rest and falls a distance of 0.5m in 1.5sec calculate the frictional torque.

mass of wheel = 3kg

Radius= 0.3m

Radius of gyration = 0.212m

## Homework Equations

Torque = mk^2a

## The Attempt at a Solution

From a prevoius question i calculated the angular acceleration to be 1.48rads.

So torque= mk^2a = 3x0.212^2x1.48

So Torque = 0.2Nm if friction is ignored.

So i have a torque 0.2Nm and angular acceleration of 1.48rads^2

Am i right in thinking Torque-frictional torque= angular acceleration?

so 0.20- frictional torque = 1.48?. This doesnt seem to work out for me. any help would be appreciated

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