Frictionles force problem with hanging mass

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SUMMARY

The problem involves two blocks, M1 (3.70 Kg) on a frictionless inclined plane at 30 degrees and M2 (2.30 Kg) hanging vertically, connected by a cord over a massless, frictionless pulley. The acceleration of both blocks can be determined using Newton's second law, F=ma. The equations derived include T = M1a and T - M2g = M2a, leading to a system of equations that can be solved for the acceleration 'a' and tension 'T'. The analysis confirms that M2 will accelerate downward due to the greater gravitational force compared to the component of M1's weight along the incline.

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Homework Statement


A block if mass M1=3.70 Kg on a frictionless plane inclined at 30 degrees is connected by a cord over a massless, frictionless pulley to a second block of mass M2= 2.30Kg. What is the magnitude of acceleration of both blocks?


Homework Equations


F=ma


The Attempt at a Solution



4gb9u.png


Fnormal-M1gsin(30)=0
T=M1a
T-M2g=May

Not really sure where to go from here since I have 2 variables T and a.
T-
 
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Shapeup said:

Homework Statement


A block if mass M1=3.70 Kg on a frictionless plane inclined at 30 degrees is connected by a cord over a massless, frictionless pulley to a second block of mass M2= 2.30Kg. What is the magnitude of acceleration of both blocks?


Homework Equations


F=ma


The Attempt at a Solution




Fnormal-M1gsin(30)=0
your geometry/trig is off, it's not the sin function here...
T=M1a
you are missing a force component in this equation
T-M2g=May
..or is it M2g -T = M2ay?? Or does it matter?
Not really sure where to go from here since I have 2 variables T and a.
T-
2 equations, 2 unknowns..are the accelerations of the masses the same?
 
Since M2*g > M1*g*sinθ, M2 moves in the downward direction.
Now write down expression for net force on M1 and M2.
 

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