FTC with a two-variable function

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SUMMARY

The discussion centers on the application of the Fundamental Theorem of Calculus (FTC) in the context of differentiating a two-variable function defined by an integral. The confusion arises regarding the term that appears as an integral of a partial derivative when differentiating first and then integrating. The correct approach involves recognizing that if F(x) = ∫a(x)b(x) f(t,x) dt, then the derivative d/dx F(x) must account for contributions from both the limits of integration and the integrand, leading to the inclusion of the additional term in the final result.

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https://en.wikipedia.org/wiki/Differentiation_under_the_integral_sign

I don't understand where the last term comes from, the one that's an integral of a partial derivative. When I solve it using the FTC I get the same answer minus that term.

If I differentiate first then integrate I get that term but then none of the others.
 
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e^(i Pi)+1=0 said:
https://en.wikipedia.org/wiki/Differentiation_under_the_integral_sign

I don't understand where the last term comes from, the one that's an integral of a partial derivative. When I solve it using the FTC I get the same answer minus that term.

If I differentiate first then integrate I get that term but then none of the others.

Work it out for yourself from first principles: if
F(x) = \int_{a(x)}^{b(x)} f(t,x) \, dt,
then
\frac{d}{dx} F(x) = \lim_{h \to 0} \frac{F(x+h) - F(x)}{h}
Work out the value of the numerator for small ##h > 0##; you will see that in general it involves several types of terms, and these give limits that are the terms in the final result you want.
 

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