Function Composition: Restrictions for Domains

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SUMMARY

The discussion focuses on the necessary restrictions for the domains of three functions \(F\), \(G\), and \(H\) to ensure that the composite functions \(G \circ F\), \(H \circ G\), \(H \circ (G \circ F)\), and \((H \circ G) \circ F\) can be defined. The key requirements established are that the image of \(F\) must be a subset of the domain of \(G\) and the image of \(G\) must be a subset of the domain of \(H\). For example, with \(F(x) = x + 5\) and \(G(x) = \frac{|x|}{x}\) for \(x \neq 0\), the conditions for proper composition are clearly outlined.

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Dustinsfl
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Given three functions $F,G,H$ what restrictions must be placed on their domains so that the following four composite functions can be defined?
$$
G\circ F,\quad H\circ G,\quad H\circ (G\circ F),\quad (H\circ G)\circ F.
$$

I need a hint or something.
 
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I'd say that in each case you'd need $\textrm{Im }F \subset D_G, \text{ I am }G \subset D_H, \text{ I am }G \circ F \subset D_H$ and $\text{Im }F \subset D_{H \circ G}$.

Taking as example your other thread, we need $\text{Im }F \subset D_G$, where $F(x) = x+5$ and

$$G(x) = \begin{cases} \frac{|x|}{x}, & \text{if } x \neq 0 \\ 1, & \text{if } x= 0. \end{cases}$$

For $\text{Im }F$ to be contained in the domain of $G$, we need to investigate the cases where $F(x) \neq 0$ and $F(x)=0$. In particular, here we have $\text{Im }F = \mathbb{R}$ and $D_G = \mathbb{R}$ since it is defined everywhere (although it isn't continuous).
 
dwsmith said:
Given three functions $F,G,H$ what restrictions must be placed on their domains so that the following four composite functions can be defined?
$$
G\circ F,\quad H\circ G,\quad H\circ (G\circ F),\quad (H\circ G)\circ F.
$$

I need a hint or something.

Hi dwsmith, :)

If \(G\circ F\) is to be defined properly the co-domain of \(F\) should be a subset of the domain of \(G\). Therefore the only restrictions in defining the above mentioned compositions are,

\[\mbox{codom }(F)\subseteq\mbox{dom }(G)\mbox{ and }\mbox{codom }(G)\subseteq\mbox{dom }(H)\]

Kind Regards,
Sudharaka.
 

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