Function differentiable, but derivative not bounded

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SUMMARY

The discussion centers on identifying a function f that is differentiable on the interval [0,1] while having an unbounded derivative f' on the same interval. Key conclusions include that f must be continuous and bounded on [0,1], yet its derivative f' must exhibit behavior that leads to unboundedness, specifically oscillating rapidly. A classic example of such a function is f(x) = x^2 * sin(1/x) for x > 0, and f(0) = 0, which demonstrates the required properties.

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Homework Statement



Give an example of a function f that is differentiable on [0,1] but its derivative is not bounded on [0,1]

Homework Equations


The Attempt at a Solution

Ok, I know that the derivative f' cannot be continuous, because then it would be bounded on [0,1]. I also know that it cannot be increasing with jump discontinuities, because the derivative has to have the intermediate value property. I also do not think (but am not 100 percent sure) that it can have any infinite discontinuities, because I think that would make f unbounded, which it cannot be on [0,1] if its differentiable on [0,1].

Any ideas?
 
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Let's gather the facts you know about the two functions:

1) f is differentiable
1a) f is continuous (follows from differentiability)
1b) f is bounded on [0,1] (follows from continuity on a compact set)

2) f' is unbounded on [0,1]

So f' must go off to infinity (or negative infinity) on [0,1]. Yet f is bounded. So what could be happening? Hint: It seems f must be oscillating really fast. What kinds of functions do this?
 

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