Function that is open but not closed?

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Homework Help Overview

The discussion revolves around identifying examples of functions that are classified as open or closed within the context of topology. Participants are exploring the definitions and properties of open and closed functions, particularly in relation to the standard topology on the real numbers.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to identify specific functions that are open but not closed, and vice versa. There are questions about the nature of functions and sets, particularly regarding expressions like "f(x) < x" and whether they qualify as functions. Some participants are considering standard functions like f(x) = x^2 and f(x) = x, while others are questioning the definitions and implications of these classifications.

Discussion Status

The discussion is ongoing, with participants expressing confusion about the definitions of open and closed functions. Some guidance has been offered regarding the need for specific examples, and there is a recognition of the distinction between functions and inequalities. Multiple interpretations of the problem are being explored, particularly regarding what constitutes an open function.

Contextual Notes

Participants are grappling with the definitions of open and closed sets in topology, and there is a lack of clarity on how these concepts apply to certain mathematical expressions. The homework context appears to impose a requirement for concrete examples of functions, which is contributing to the confusion.

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Homework Statement


An example of a function that is open but not closed, and an example of a function that is closed but not open.

Homework Equations


The function f is open (closed) if f[A] is open (closed) for each open (closed) set A in X.


The Attempt at a Solution


This is a topology question and I don't understand it. The only attempt I have made was to guess at a function with < instead of =. If somebody could clarify on the point of what these "functions" look like. Are they the standard, f(x) = x^2 type, or something else?
 
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They can be "standard." For example, if you give \mathbb{R} its usual topology, then f(x)=x^2 (as a function from \mathbb{R} to \mathbb{R}) is closed but not open.
 
I was on the right track?

Is f(x) < x , open but not closed? Is any function with < or > open but not closed?

EDIT: I meant, given the usual topology and from R --> R
 
I have no idea what you mean by "f(x)< x" being "open but not closed". That is neither a function nor a set so "open" and "closed" do not apply.

It might be good for you to think about what a function is first. The problem asks for specific examples of functions.
 
HallsofIvy said:
I have no idea what you mean by "f(x)< x" being "open but not closed". That is neither a function nor a set so "open" and "closed" do not apply.

It might be good for you to think about what a function is first. The problem asks for specific examples of functions.

I have thought about what you said. Is y<x an open function?

EDIT: I am having trouble determining the difference between open, and open function.
 
Unassuming said:
I have thought about what you said. Is y<x an open function?
The real question is: is y<x a function?

Maybe a better question would be: what exactly do you mean by "y<x"?!
 
I don't feel that it is a function, but my book says that y^2 + x^2 < 9 is open. It doesn't specify that it is an open function though. I also don't have any other examples.

Is there a function that is open?

EDIT: I won't bother you guys (gals) too much more but here is my last attempt. The
function? f(x,y) = x^2 + y^2 < 9 . ??
 
Last edited:
Unassuming said:
I don't feel that it is a function, but my book says that y^2 + x^2 < 9 is open.
That is not a function. It is, however, an open set.

Consider the simple function f(x)=x. The image of this function for any open set A is the open set A, and the image for any closed set B is the closed set B. f(x)=x is both an open and closed function. So this simple function doesn't work as far as solving your problem.

You need to come up with functions f and g where f is open but not closed and g is closed but not open. What this means is that f(A) is an open set for any open set A in the domain of f, but f(B) is not a closed set for any closed set in the domain of f, and similar for g.
 
What is it that makes f(x)=x^2 closed but not open? I do not understand how this is different from f(x)=x which is open and closed.
 
  • #10
Unassuming said:
What is it that makes f(x)=x^2 closed but not open? I do not understand how this is different from f(x)=x which is open and closed.
Given f(x)=x^2, what is the image of some open set that contains zero?
 

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