Functional equation Riemann Zeta function

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SUMMARY

The discussion centers on the Riemann functional equation, specifically its two forms and their relationship to the duplication theorem of the Gamma function. The equation is expressed as ## \pi^{-s/2}\Gamma\left(\frac{s}{2}\right)\zeta(s)=\pi^{-\frac{1-s}{2}}\Gamma\left(\frac{1-s}{2}\right)\zeta(1-s) ##. Participants seek clarification on linking Corollary 2 to Theorem 1, emphasizing the symmetry in the functional equation. The connection between the definitions of ## \xi(s) ## and ## \xi(1-s) ## is also highlighted, demonstrating the inherent properties of the Riemann zeta function.

PREREQUISITES
  • Understanding of the Riemann zeta function
  • Familiarity with the Gamma function and its duplication theorem
  • Basic knowledge of functional equations in mathematics
  • Experience with mathematical proofs and theorems
NEXT STEPS
  • Study the properties of the Riemann zeta function in detail
  • Explore the duplication theorem of the Gamma function
  • Investigate the implications of the functional equation on analytic continuation
  • Review mathematical proofs related to Corollary 2 and Theorem 1
USEFUL FOR

Mathematicians, students of number theory, and anyone interested in the properties and applications of the Riemann zeta function and functional equations.

Lapidus
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There are two forms of Riemann functional equation. One is more symmetric and follows from the other and the duplication theorem of the Gamma function. At least, that's been claimed here:

https://terrytao.wordpress.com/2014...unction-and-the-functional-equation-optional/

Can someone help me linking Corollary 2 to Theorem 1?

I am just a amateurish layman who tries to piece things together from various sources from the net. So I got confused when I found out that people use two different forms of the functional equation.

Any help, hints or links are very much appreciated!
 
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Another way to write the functional equation for ##\zeta## in Theorem 1 is

## \pi^{-s/2}\Gamma\left(\frac{s}{2}\right)\zeta(s)=\pi^{-\frac{1-s}{2}}\Gamma\left(\frac{1-s}{2}\right)\zeta(1-s) ##

so if you take as definition of ## \xi(s) ## the formula (6) in the corollary and using the functional formula above you can see that

## \xi(s)=\xi(1-s) ##
 
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