Functions: Input of a function is another function.

[Joked]

The input for a function can be another function. If h(x) = 2x - 5, determine a simplified expression for each of the following.

a) h(4x) b) h(2x+3) h(x/2-1)
h(x) = 2x - 5For a) h(4x) it can be h(4x) = (4)2x - 5 = 8x -5 however I am not sure why the 4 was not applied to the -5 also.

I am not sure how to solve this problem. If anyone could give me a link to a website that explains it and gives a proof for it, I would appreciate that act very much.

 

[Pyrrhus]

Look up function composition for details.

The basic ideas is that the argument of your function is evaluated at the new function, that means replace the x of f(x) as they appear in the definition of your f(x) with the other function g(x) or f(g(x)).

 

[Joked]

Thank you Pyrrhus

I looked it up some more and it clicked.

I do not know how to close a thread.