Functions not satisfying parallelogram identity with supremum norm

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SUMMARY

The discussion centers on identifying two continuous functions, f and g, on the interval [0,1] that do not satisfy the parallelogram identity with respect to the supremum norm. The specific functions provided are f(x) = x and g(x) = x - 1. These functions demonstrate that 2 ||f||^2_{sup} + 2 ||g||^2_{sup} does not equal ||f+g||^2_{sup} + ||f-g||^2_{sup}, thus serving as a valid counterexample to the identity.

PREREQUISITES
  • Understanding of continuous functions on the interval [0,1]
  • Familiarity with the supremum norm (|| \cdot ||_{sup})
  • Knowledge of the parallelogram identity in functional analysis
  • Basic skills in function manipulation and evaluation
NEXT STEPS
  • Explore the properties of the supremum norm in functional analysis
  • Investigate other examples of functions that violate the parallelogram identity
  • Learn about the implications of the parallelogram identity in Hilbert spaces
  • Study the relationship between continuous functions and norms in various function spaces
USEFUL FOR

Mathematics students, particularly those studying functional analysis, as well as educators looking for examples of the parallelogram identity and its applications in continuous function spaces.

JackTheLad
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Homework Statement


Find two functions f, g \in C[0,1] (i.e. continuous functions on [0,1]) which do not satisfy

2 ||f||^2_{sup} + 2 ||g||^2_{sup} = ||f+g||^2_{sup} + ||f-g||^2_{sup}

(where || \cdot ||_{sup} is the supremum or infinity norm)

Homework Equations


Parallelogram identity: 2||x||^2 + 2||y||^2 = ||x+y||^2 + ||x-y||^2 holds for any x,y


The Attempt at a Solution


Honestly no idea.
 
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Just try some functions. It's really not hard to find an example that doesn't work.
 
For posterity, two functions which fit nicely are
f(x) = x
g(x) = x-1


(I had tried lots of functions but they worked; not very helpful response)
 

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