Fundamental frequency of oscillation in 2 ropes

In summary: We eliminated velocity. Look at your equation in post #3. The are four variables in there. Which one has not been mentioned?
  • #1
goonking
434
3

Homework Statement


upload_2015-9-24_1-36-50.png


Homework Equations

The Attempt at a Solution


if the material are the same in both strings, then the density should be the same.
v = sqrt (tension/μ)

tension in the first string should be 30 kg x 9.8 m/s^2 = 294 N

next,

v = λƒ

and string#2 needs to have twice the frequency of string#1

and this is where I am stuck, don't know where to proceed from here :cry:

do I need wavelength here? if so, how would i find it?
 
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  • #2
You have two equations involving v, but you are not very interested in v. So what should you do with the two equations?
Next, you have the same equations for two different cases. Some of the variables are the same for both cases. It helps to clarify things if you create different symbols (like T1, T2) wherever the variables are different. That should produce two equations, neither involving v.
 
  • #3
haruspex said:
You have two equations involving v, but you are not very interested in v. So what should you do with the two equations?
Next, you have the same equations for two different cases. Some of the variables are the same for both cases. It helps to clarify things if you create different symbols (like T1, T2) wherever the variables are different. That should produce two equations, neither involving v.
do I equate them both? :

λƒ = sqrt (tension/μ) ?

also, what is interchangeable in each string with masses? do they both have the same wavelength? do they have the same velocity?
 
  • #4
goonking said:
do I equate them both? :

λƒ = sqrt (tension/μ) ?

also, what is interchangeable in each string with masses? do they both have the same wavelength? do they have the same velocity?
You know the tensions (different) and the wavelengths (different). You know the frequencies are different. What does that leave?
 
  • #5
haruspex said:
You know the tensions (different) and the wavelengths (different). You know the frequencies are different. What does that leave?
velocity? but if tension is different then velocity should be different too, right?
 
  • #6
goonking said:
velocity? but if tension is different then velocity should be different too, right?
We eliminated velocity. Look at your equation in post #3. The are four variables in there. Which one has not been mentioned?
 

1. What is the fundamental frequency of oscillation in 2 ropes?

The fundamental frequency of oscillation in 2 ropes refers to the lowest possible frequency at which the ropes can oscillate in a standing wave pattern. This frequency is determined by the properties of the ropes, such as their length, tension, and mass per unit length.

2. How is the fundamental frequency of oscillation in 2 ropes calculated?

The fundamental frequency can be calculated using the formula f = 1/2L * √(T/μ), where L is the length of the ropes, T is the tension in the ropes, and μ is the mass per unit length of the ropes. This formula is derived from the wave equation and takes into account the physical properties of the ropes.

3. Why is the fundamental frequency of oscillation important?

The fundamental frequency of oscillation is important because it determines the natural frequency of the ropes. This frequency can affect the stability and resonance of the ropes, and can also be used to tune musical instruments or study the properties of materials.

4. How does the fundamental frequency of oscillation change with different properties of the ropes?

The fundamental frequency of oscillation is directly proportional to the length of the ropes and the square root of the tension, and inversely proportional to the square root of the mass per unit length. This means that a longer rope or a higher tension will result in a higher frequency, while a heavier rope will result in a lower frequency.

5. Can the fundamental frequency of oscillation be changed?

Yes, the fundamental frequency of oscillation can be changed by altering the properties of the ropes. This can be done by adjusting the length, tension, or mass per unit length of the ropes. Additionally, the fundamental frequency can also be affected by external factors such as temperature and humidity.

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