G_ab: Calculating a Corrected Value

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Discussion Overview

The discussion revolves around the calculation of the corrected value of the Einstein tensor \( G_{ab} \) in the context of general relativity. Participants are examining the relationships between the Ricci tensor \( R_{ab} \), the Ricci scalar \( R \), and the metric tensor \( g_{ab} \), focusing on the proper application of indices and summation conventions.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant proposes the equation \( G_{ab} = R_{ab} - \frac{1}{2} R g_{ab} \) and suggests that this simplifies to \( G_{ab} = \frac{1}{2} R_{ab} \), seeking corrections to this approach.
  • Another participant argues that the indices must be treated correctly, stating that \( a \) and \( b \) cannot be repeated and summed over, and suggests using \( R = g^{cd} R_{cd} \) instead.
  • It is noted that \( g^{ab} g_{ab} = I \), the identity matrix, under certain conditions, specifically when dealing with square matrices and their contraction with the Ricci tensor.
  • Further clarification is provided that \( g^{ab} g_{bc} = \delta^a_c \), indicating a need for careful consideration of index notation and summation conventions.
  • One participant mentions that using the equation \( G_{ab} = R_{ab} - \frac{1}{2} R_{cd} \) would yield all elements of the Ricci tensor in each cell, questioning the validity of the original equation proposed.

Areas of Agreement / Disagreement

Participants express differing views on the correct treatment of indices and the validity of the proposed equations. There is no consensus on the correct formulation or interpretation of the equations involved.

Contextual Notes

Participants highlight the importance of adhering to summation conventions and avoiding the repetition of indices, which may lead to confusion or errors in calculations.

Philosophaie
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G_ab = R_ab - 1/2 * R * g_ab

and

R = g^(ab) * R_ab

then

G_ab = R_ab - 1/2 * R_ab * (g^(ab) * g_ab)
=1/2 * R_ab

for this abomination someone please correct me.
 
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No. a and b are free indices on the right, so a and b have to be free indices on right, i.e., they cannot be repeated and summed over.

Use [itex]R = g^{cd} R_{cd}[/itex] instead of [itex]R = g^{ab} R_{ab}[/itex].

Also, what does [itex]g^{ab} g_{ab}[/itex] equal?
 
g^(ab) * g_ab = I, the Identity Matrix only if a square matrix and when dotted with R_ab gives you back R_ab.
 
Philosophaie said:
g^(ab) * g_ab = I

No.

It is true that

[tex]g^{ab} g_{bc} = \delta^a_c.[/tex]

Think about it some more.
 
Philosophaie said:
g^(ab) * g_ab = I, the Identity Matrix only if a square matrix and when dotted with R_ab gives you back R_ab.

That term doesn't appear in the equation. What you have is:

[tex]g^{cd} g_{ab}[/tex]

Where the left metric tensor is contracted with the Ricci tensor. Remember not to repeat indices more than twice. It messes up the summation convention. Use different letters like George Jones said.
 
Last edited:
If you use the equation:

G_ab = R_ab - 1/2 * R _cd

You will get all the elements of the Ricci Tensor in each cell. Is really what the equation is?
 

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