Gamma Function Limits: Proving \Gamma(x) \to 0 as x \to -\infty

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The discussion centers on proving that the absolute value of the gamma function, Γ(x), approaches zero as x tends to negative infinity. Participants explore the use of Gauss's Formula but find it too complex for their needs. They note that the gamma function has poles at non-positive integers, suggesting that it may be more effective to define the function for x less than zero while excluding these poles. One user proposes a new approach by considering a sequence that converges to zero as n increases. The conversation concludes with a commitment to further explore this idea without relying on Gauss's Formula.
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Homework Statement



The absolute value of the gamma function \Gamma (x) that is defined on the negative real axis tends to zero as x \to - \infty. Right? But how do I prove it?

Homework Equations


The Attempt at a Solution



I've tried to use Gauss's Formula:

\Gamma(x)=\lim_{n\to\infty}\frac{n!n^{z}}{z(z+1) \cdots (z+n)}.

Should I keep going in this direction?

But frankly, the calculation gets too technical so it'd be better if there is a bit easier way.
 
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julypraise said:

Homework Statement



The absolute value of the gamma function \Gamma (x) that is defined on the negative real axis tends to zero as x \to - \infty. Right? But how do I prove it?



Homework Equations





The Attempt at a Solution



I've tried to use Gauss's Formula:

\Gamma(x)=\lim_{n\to\infty}\frac{n!n^{z}}{z(z+1) \cdots (z+n)}.

Should I keep going in this direction?

But frankly, the calculation gets too technical so it'd be better if there is a bit easier way.

Have you ever looked at the graph of the Gamma function on the real line? Look in here:
http://en.wikipedia.org/wiki/Gamma_function . Does it look to you that ##\Gamma(x) \rightarrow 0 ## as ##x \rightarrow -\infty?##

RGV
 


Ray Vickson said:
Have you ever looked at the graph of the Gamma function on the real line? Look in here:
http://en.wikipedia.org/wiki/Gamma_function . Does it look to you that ##\Gamma(x) \rightarrow 0 ## as ##x \rightarrow -\infty?##

RGV

Ah.. I know what you mean. Maybe I need to modify my problem first. I know it has poles on non-positive integers. But excluding poles, it seems the absolute value of the gamma function tends to zero as x \to - \infty.

(http://en.wikipedia.org/wiki/File:Complex_gamma_function_abs.png)

May I define

f(x) = \Gamma (x) only for x<0 \quad \mbox{and} \quad x \neq -1, -2, -3, -4, \dots

and then prove |f(x)| \to 0 as x \to - \infty?
 


Ah... MY BAD! sorry.. what was I thinking... Let me clarify once more:

Take x_{n} \in (-n,1-n). Then \Gamma (x_{n}) \to 0 as n \to \infty.

I think I have an idea to solve it without using Gauss's Formula. After I try, I will put on the thread.

Anyway thanks for reminding me.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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