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Faiq
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Homework Statement
Why is the formula ##p = \frac{1}{3}\rho<c^2>## used to calculate the mean square speed at 273K?
Why 273K?
The confusion I had was why is that formula only applicable for the 273K. That's to say why I can't just put that value down for 546K? Later I realized, the pressure inserted in those equations are the indicator of what temperature should the RMS value be for.Borek said:You are given pressure and density at 273 K and asked to calculate rms at exactly this temperature, I don't see where is the problem?
Missing:Faiq said:Homework Statement
Any word or sentence missing from this full problem statement ? If no, then a list of all variables is good to have at hand. For you too.Faiq said:The density of a gas at a temperature of ##273~K## and a pressure of ##1.02*10^5~ Pa## is ##0.9kgm^{-3}##. It may be asssumed to be an ideal gas.
Calculate rms speed at 273K and 546K.
What given equation ?Faiq said:For 273, we were supposed to use the given equation and for second we were supposed to used the ratio of mean square speed and temperature.
come from ? From the textbook or from the problem statement ? (or perhaps from the solution manual ?)Faiq said:formula ##p = \frac{1}{3}\rho<c^2>##
The mean square speed at 273K is an important parameter in gas laws because it is directly related to the temperature of the gas. It helps us understand the kinetic energy of gas particles, which in turn affects the pressure, volume, and temperature of the gas.
The mean square speed at 273K represents the average speed of gas particles at a temperature of 273 Kelvin. It is calculated by taking the square root of the average of the squared speeds of individual gas particles.
The mean square speed at 273K is equal to three times the root mean square speed. This relationship allows us to easily calculate the mean square speed if we know the root mean square speed or vice versa.
The mean square speed at 273K increases as the temperature of the gas increases. This is because as temperature increases, the kinetic energy of gas particles also increases, leading to higher speeds and a larger mean square speed.
273K is the standard temperature at which gas laws are typically studied. By using this temperature, we can compare the mean square speeds of different gases and determine their relative speeds and kinetic energies. It also allows for easier conversion between different temperature units, such as Celsius and Kelvin.