How much oxygen escaped from the container?

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SUMMARY

The discussion focuses on calculating the mass of oxygen that escaped from a 56-liter container after a pressure drop from 4 atm to 3.5 atm. The initial calculation used gauge pressure, leading to an incorrect mass of 102.3 grams. The correct approach involves using absolute pressure, resulting in a mass of 341.1 grams for the initial state, based on the molar mass of O2 being 32 grams per mole. The final calculation shows that 50.1 grams of oxygen escaped due to the pressure drop.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Knowledge of molar mass and atomic mass, specifically for O2
  • Familiarity with pressure units, including gauge and absolute pressure
  • Basic algebra for manipulating equations
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  • Learn about the differences between gauge pressure and absolute pressure
  • Explore the concept of molar mass and its significance in gas calculations
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Karol
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Homework Statement


Into a 56[liter] container oxigen is filled in with manometric pressure of 4[atm] and temp' 470C. what is the mass.
Then a leak happens and the pressure drops to 3.5[atm] and temp' 270C.
How much oxigen escaped.

Homework Equations


$$PV=nRT$$
$$R\left[\frac{liter\cdot atm'}{mole\cdot ^0K}\right]=0.08208$$
Atomic number O2=16

The Attempt at a Solution


The initial conditions: ##3[atm]\cdot 56[liter]=n\cdot 0.08208\cdot 320^0K\rightarrow n=6.4[mole]##
$$m=6.4\cdot 16=102.3[gr]$$
Second stage:
$$\frac{P_1V_1}{n_1T_1}=\frac{P_2V_2}{n_2T_2}\rightarrow\frac{P_1V_1}{m_1T_1}=\frac{P_2V_2}{m_2T_2}$$
Our volume is fixed, so: ##\frac{3}{102.3\cdot 320}=\frac{2.5}{m_2\cdot 300}\rightarrow m_2=90.97[gr]##
Is it correct?
 
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Karol said:

Homework Statement


Into a 56[liter] container oxigen is filled in with manometric pressure of 4[atm] and temp' 470C. what is the mass.
Then a leak happens and the pressure drops to 3.5[atm] and temp' 270C.
How much oxigen escaped.

Homework Equations


$$PV=nRT$$
$$R\left[\frac{liter\cdot atm'}{mole\cdot ^0K}\right]=0.08208$$
Atomic number O2=16

The Attempt at a Solution


The initial conditions: ##3[atm]\cdot 56[liter]=n\cdot 0.08208\cdot 320^0K\rightarrow n=6.4[mole]##
$$m=6.4\cdot 16=102.3[gr]$$

Why did you calculate with 3 atm?
And the oxygen gas consists of O2 molecules. The atomic mass of oxygen is 16 g, but you have to work with the molar mass.
 
manometric pressure is the pressure above atmospheric, right? so i have to take absolute pressures, it's then 5 atm.
And the molar mass is 32[gr]
$$5[atm]\cdot 56[liter]=n\cdot 0.08208\cdot 320^0K\rightarrow n=10.7[mole]$$
$$m=10.7\cdot 32=341.1[gr]$$
 
Karol said:
manometric pressure is the pressure above atmospheric, right? so i have to take absolute pressures, it's then 5 atm.
And the molar mass is 32[gr]
$$5[atm]\cdot 56[liter]=n\cdot 0.08208\cdot 320^0K\rightarrow n=10.7[mole]$$
$$m=10.7\cdot 32=341.1[gr]$$

I know pressure above atmospheric as "gauge pressure". You have to know what manometric pressure is. I never heard that.
 
Yes, it's gauge pressure
 

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