Pump compresses air into a tank

  • Thread starter Karol
  • Start date
  • #1
1,380
22

Homework Statement


A cylindrical pump of length 25[cm] pumps air in atmoshpheric pressure ant temp 270C into a big tank. the manometric pressure in the tank is 4[atm]. at which distance will the air start entering the tank.

Homework Equations


In adiabatic process: ##P_1V_1^\gamma=P_2V_2^\gamma##
γ for air=1.4

The Attempt at a Solution


I assume an adiabatic process. i think that manometric pressure is gauge pressure:
$$P_1V_1^\gamma=P_2V_2^\gamma\rightarrow V_2=\sqrt[\gamma]{\frac{P_1}{P_2}V^{\gamma}}$$
$$\rightarrow \ln V_2=\ln\left(\frac{P_1}{P_2}V_1^{\gamma}\right)^{\frac{1}{\gamma}}=\frac{1}{\gamma}\ln\left(\frac{P_1}{P_2}V_1^{\gamma}\right)$$
$$\ln V_2=\frac{1}{\gamma}\left[\ln\left(P_1V_1^{\gamma}\right)-\ln P_2\right]=\frac{1}{\gamma}\left[\ln P_1+\gamma\ln V_1-\ln P_2\right]$$
The volume is area A times length x. for our data:
$$\ln V_2=\ln A+\ln x=\frac{1}{1.4}\left[\ln 0+1.4\ln (A\cdot 25)-\ln 5\right]=\frac{1}{1.4}\left[1.4(\ln A+\ln 25)-\ln 5\right]$$
$$\ln A+\ln x=\ln A+\ln 25-\ln 5\rightarrow \ln x=\ln\left(\frac{25}{5}\right)=\ln 5\rightarrow x=5[cm]$$
It should be 7.9[cm] before the end of the cylinder.
If i don't assume adiabatic process and only use ##PV=nRT## i have 2 unknowns: the distance and the final temperature.
 

Answers and Replies

  • #2
20,844
4,543
You forgot to divide ln(P2) by 1.4.
Also, P1 = 1, so you shouldn't have ln(0) in the equation.
Also, it was not necessary to work this problem in terms of natural logs.

Chet
 
  • #3
1,380
22
$$\ln A+\ln x=\ln A+\ln 25-\frac{\ln 5}{1.4}\rightarrow x=7.9[cm]$$
Which other way besides natural logs?
 
  • #4
20,844
4,543
$$\ln A+\ln x=\ln A+\ln 25-\frac{\ln 5}{1.4}\rightarrow x=7.9[cm]$$
Which other way besides natural logs?
[tex]\frac{V_2}{V_1}=\left(\frac{P_1}{P_2}\right)^{1/\gamma}[/tex]
[tex]\frac{x}{25}=0.2^{(1/\gamma)}[/tex]
Chet
 
  • #5
1,380
22
Thanks Chet
 

Related Threads on Pump compresses air into a tank

  • Last Post
Replies
1
Views
3K
Replies
10
Views
2K
  • Last Post
Replies
17
Views
1K
Replies
6
Views
1K
  • Last Post
Replies
7
Views
575
  • Last Post
Replies
6
Views
496
Replies
31
Views
2K
  • Last Post
Replies
2
Views
537
  • Last Post
Replies
8
Views
26K
Top