Gauss-Theorem on a solid dielectric sphere

  • #1
Guillem_dlc
184
15
Homework Statement:
We have an Q=2nC-load uniformly distributed on a solid dielectric sphere of R=1m-radius with center at the coordinate origin of an Oxyz axis system. At the O centre of this sphere there is a negative point charge q=−1nC. Let us consider the points of space P=(0.3,0.4,0)m and S=(1,2,2)m. Calculate:

(a) The electric field vector at points P and Q.

(b) The difference in potential between these points, i.e. V(S)−V(P).
Relevant Equations:
Gauss-Law
The load system formed by the point load and the load distribution generates two regions in space corresponding to r<1m and r>1m, i.e. inside and outside the sphere. Given the symmetry of the distribution, by means of the Gaussian theorem we can find the modulus of the field at a distance r from the center.
  • Region r<1m:
    Captura de pantalla de 2020-01-01 01-32-28.png
To find the electric field vector at point P we need the vector that goes from point O to point P, i.e. r→=(0.3,0.4,0), whose module is worth r=0.5. Thus, the field vector is given by:
Captura de pantalla de 2020-01-01 01-32-04.png


Until the last equation I have it well but the result gives me different. The first component is: [−36+9]⋅(0.3)/(0.5) isn't it? Or I don't see it ...
 

Answers and Replies

  • #2
TSny
Homework Helper
Gold Member
13,964
4,137
Yes, it looks like the final answer has the decimal points in the wrong place.
 
  • Like
Likes Guillem_dlc

Suggested for: Gauss-Theorem on a solid dielectric sphere

  • Last Post
Replies
14
Views
820
  • Last Post
Replies
20
Views
923
Replies
78
Views
3K
Replies
6
Views
633
  • Last Post
Replies
5
Views
266
  • Last Post
Replies
1
Views
537
Replies
19
Views
901
Top