Gauss-Theorem on a solid dielectric sphere

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Guillem_dlc
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Homework Statement
We have an Q=2nC-load uniformly distributed on a solid dielectric sphere of R=1m-radius with center at the coordinate origin of an Oxyz axis system. At the O centre of this sphere there is a negative point charge q=−1nC. Let us consider the points of space P=(0.3,0.4,0)m and S=(1,2,2)m. Calculate:

(a) The electric field vector at points P and Q.

(b) The difference in potential between these points, i.e. V(S)−V(P).
Relevant Equations
Gauss-Law
The load system formed by the point load and the load distribution generates two regions in space corresponding to r<1m and r>1m, i.e. inside and outside the sphere. Given the symmetry of the distribution, by means of the Gaussian theorem we can find the modulus of the field at a distance r from the center.
  • Region r<1m:
    Gauss's law equation for the field inside a charged sphere: E1 times 4 pi r squared equals Qint over epsilon 0, which equals (q + Q r^3/R^3) over epsilon 0, giving E1 = -9/r^2 + 18r.
To find the electric field vector at point P we need the vector that goes from point O to point P, i.e. r→=(0.3,0.4,0), whose module is worth r=0.5. Thus, the field vector is given by:
Typeset equation: E1 vector = E1 times r-hat, equal to [-9/(0.5)^2 + 18(0.5)] times (0.3, 0.4, 0)/0.5, equal to (-1.62, -2.16, 0) N/C.


Until the last equation I have it well but the result gives me different. The first component is: [−36+9]⋅(0.3)/(0.5) isn't it? Or I don't see it ...
 
Yes, it looks like the final answer has the decimal points in the wrong place.
 
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