Gaussian Surface Electric Field Problem

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SUMMARY

The discussion centers on the electric field generated by a point charge q located at the center of an uncharged spherical thin metallic shell. The electric field inside the shell is confirmed to be zero, while outside, it behaves as if it were a point charge, described by the equation E = kQ/4πε_0. The shell effectively shields the interior from external electric fields but does not shield its own field. The presence of the point charge does not exert a force on the charge inside the shell, resolving the apparent contradiction to Newton's 3rd Law through the polarization of the shell.

PREREQUISITES
  • Understanding of electric fields and Gauss's Law
  • Familiarity with the concept of electric shielding
  • Knowledge of point charges and their interactions
  • Basic grasp of Newton's Laws of motion
NEXT STEPS
  • Study Gauss's Law in detail, particularly its application to spherical symmetry
  • Explore the concept of electric shielding and its practical applications
  • Investigate the behavior of electric fields in conductive materials
  • Examine the implications of Newton's 3rd Law in electrostatics
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This discussion is beneficial for physics students, educators, and anyone interested in electrostatics, particularly those studying electric fields and their interactions with conductive materials.

wompkins
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Homework Statement


An uncharged spherical thin metallic shell has a point charge q at its center. Find expressions for the electric field
  1. Inside the shell
  2. Outside the shell
  3. has the shell any effect on the field due to q?
  4. has the presence of q any effect on the shell?
  5. if a second point charge is held outside the shell, does this outside chage feel a force
  6. does the inside charge feel a force?
  7. what is the apparent contradiction to Newton's 3rd Law
  8. What is the resolution to the apparent contradiction?

Homework Equations



∫E*dA = Q/ε_0 where Q is net enclosed charge

The Attempt at a Solution



  1. E-field inside metallic shell is 0
  2. Outside it is like that of a point charge E = kQ/4πε_0
  3. Yes the shell "shields" the field inside the shell to zero but outside acts like a normal E-field
  4. It will polarize the metallic shell creating the E-field from the surface of the shell
  5. Yes it will feel a force and it will be equal to qE where q is the second charge outside the shell and E is from part 2
  6. The inside force will NOT feel a force, otherwise it would move
  7. How can one feel a force but the other can't is the contradiction
  8. The fact that the metallic shell "shields" the charge and get polarized by both charges allows the inner charge to feel no force

I feel like I get the first 3 parts, but 4-8 are just my intuition and was wondering if it was correct train of thought. If not just give me a hint in the right directions please!
 
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wompkins said:

Homework Statement


An uncharged spherical thin metallic shell has a point charge q at its center. Find expressions for the electric field
  1. Inside the shell
  2. Outside the shell
  3. has the shell any effect on the field due to q?
  4. has the presence of q any effect on the shell?
  5. if a second point charge is held outside the shell, does this outside chage feel a force
  6. does the inside charge feel a force?
  7. what is the apparent contradiction to Newton's 3rd Law
  8. What is the resolution to the apparent contradiction?


Homework Equations



∫E*dA = Q/ε_0 where Q is net enclosed charge

The Attempt at a Solution




[1]E-field inside metallic shell is 0

Wrong. Surround the central charge with a concentric sphere of radius r less then the radius of the metal sphere. What is the electric field at r?

wompkins said:
[2]Outside it is like that of a point charge E = kQ/4πε_0
[3]Yes the shell "shields" the field inside the shell to zero but outside acts like a normal E-field

It shields the central charge from outside fields, but not from its own field.

wompkins said:
[4]It will polarize the metallic shell creating the E-field from the surface of the shell
[5]Yes it will feel a force and it will be equal to qE where q is the second charge outside the shell and E is from part 2
[6]The inside [STRIKE]force[/STRIKE] charge will NOT feel a force, otherwise it would move
[7]How can one feel a force but the other can't is the contradiction
[8]The fact that the metallic shell "shields" the charge and get polarized by both charges allows the inner charge to feel no force


I feel like I get the first 3 parts, but 4-8 are just my intuition and was wondering if it was correct train of thought. If not just give me a hint in the right directions please![/QUOTE]
 
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