Gauss's Law and charged conductors

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SUMMARY

In the discussion regarding Gauss's Law and charged conductors, it is established that a conductor with a net charge of +Q and a point charge of -Q within a hollow cavity results in a charge of 0 on the outer surface of the conductor. The inner surface acquires a charge of +Q to neutralize the -Q point charge, leaving no excess charge to distribute on the outer surface. This conclusion is derived from the principles of electrostatics and the behavior of conductors in electrostatic equilibrium.

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A conductor carries a net charge +Q. There is a hollow cavity inside the conductor that contains a point charge -Q. In electrostatic equilibrium,what is the charge on the outer surface of the conductor?

A. -2Q
B. -Q
C. 0
D. Q
E. 2Q


I know that the answer is 0, however, I cannot understand why. i would think that the inner surface of the conductor is +Q to offset the -Q point charge inside, which would make the outer surface +Q in order to account for the net +Q charge. However, that is not the case.

Can some one please offer me some help understanding this problem?Thanks so much
 
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If the charge on the inner surface of the conductor is +Q, and the net charge on the conductor is also +Q, how much charge is left over to distribute on the outer surface?
 
Oh ok, I see. It's 0. For some reason i thought that the +Q and the -Q would cancel out.
 

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