Is Gauss's Law in Differential Form Dependent on Position?

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SUMMARY

Gauss's Law in differential form is expressed as \(\nabla \cdot \vec{E}(\vec{r}) = \rho(\vec{r})/\epsilon_0\), indicating that the electric field \(\vec{E}\) and charge density \(\rho\) are functions of position. The omission of the position variable is common but understood in context. Applying the divergence theorem allows for the derivation of Gauss's integral law, confirming the relationship between the differential and integral forms of Gauss's Law.

PREREQUISITES
  • Understanding of vector calculus, specifically divergence.
  • Familiarity with electromagnetic theory, particularly Gauss's Law.
  • Knowledge of charge density and its relation to electric fields.
  • Proficiency in applying the divergence theorem in physics.
NEXT STEPS
  • Study the divergence theorem in detail and its applications in electromagnetism.
  • Explore the integral form of Gauss's Law and its derivation from the differential form.
  • Investigate the implications of position-dependent electric fields in various physical scenarios.
  • Learn about Maxwell's equations and their interrelations, particularly focusing on Gauss's Law.
USEFUL FOR

Students of physics, particularly those studying electromagnetism, as well as educators and professionals seeking to deepen their understanding of Gauss's Law and its applications in various contexts.

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Homework Statement


Gauss's Law is often given as:

\nabla \cdot \vec{E} = \rho/ \epsilon_0

However E is, in general a function of position, so the equation is really
\nabla \cdot \vec{E}(\vec{r}) = \rho(\vec{r}) /\epsilon_0
correct?

Homework Equations


The Attempt at a Solution

 
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Yes. The (r) is often left out, but understood.
Just apply the divrgence theorem to get Gauss's integral law.
 

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