Gauss's Law, Sphere (Electric Field

  • Thread starter jegues
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Homework Statement



See figure attached.

Homework Equations





The Attempt at a Solution



I'm extremely confused.

For r<1,

The total charge enclosed should always be,

[itex] \rho \frac{4}{3\epsilon_{0} \epsilon_{r}} \pi r^{3} = \oint _{S} \vec{E} \cdot \vec{dA} = I[/itex]

The electric field will disperse radially out of the sphere, in the same direction as [itex]\vec{dA}[/itex] so,

[itex]I = E\oint_{S} dA = 4\pi r^{2}E[/itex]

Thus,

[itex]E = \frac{\rho r}{3 \epsilon_{0} \epsilon_{r}}[/itex]

I'm confused about what is suppose to change in the region r > 1 ?

Can someone explain?
 

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Answers and Replies

  • #2
SammyS
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The charge density is zero for r > 1.
 

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