Upper Bound of H in GCSE Maths

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SUMMARY

The discussion centers on calculating the upper bound of H in a GCSE Maths problem, specifically using the formula (24.45^2)/(2*9.85). The participant calculated H as 30.3 (to three significant figures) but found a discrepancy with the model answer. The correct approach involves using the upper bound of velocity (v) and the lower bound of gravitational acceleration (g) to accurately determine H. The participant was misled by the assumption that both upper bounds should be used in the calculation.

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tomtomtom1
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Hi all

I have another upper/low bound question, i have attached the question to this thread.

The bit i am having trouble with is part (II) i.e. calculate the upper bound of H.

I attempted this and got: -

(24.45^2)/(2*9.85) = 30.34530457

H = 30.3 (3 sig fig)

The problem is that my answer differs from the model answer shown in the attachment, the reason why i did what i did was because the question stated find the Upper Bound of H, so i thought i need to use the upper bound of v & g to calculate the upper bound of H, why am i incorrect?

Thanks
 

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The upper bound of 1/g is found when the lower bound of g is used.

Same thing with subtraction: upper bound of 1.7 - 1.2 is 1.75 - 1.15 = 0.6.
And lower bound is 0.4. With your method upper and lower bound would be the same as the calculated difference itself...
 

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