General Determine 2sinx + cosecx - 3 = 0

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Homework Help Overview

The problem involves determining the general solution of the equation 2sinx + cosecx - 3 = 0, which falls under trigonometric equations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the definition of cosecx and suggest manipulating the equation by multiplying through by sinx. There are attempts to factor the resulting quadratic expression and check potential solutions. Questions arise regarding the correctness of the derived solutions and the need to verify them against the original equation.

Discussion Status

The discussion is active, with participants exploring different interpretations of the equation and checking the validity of proposed solutions. Some guidance has been offered regarding the need to provide a general solution rather than a specific range.

Contextual Notes

There is a noted confusion regarding the correct formulation of the quadratic equation derived from the original problem, which has led to varying interpretations of the solutions. Participants are also reminded to consider the general solution in their responses.

DERRAN
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Homework Statement


determine the general solution of the equation:
2sinx +cosecx -3 = 0


Homework Equations





The Attempt at a Solution


Dont know what to do need help please.
 
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What is cosecx equal to?

When you find that, try multiplying by sinx throughout and see what happens from there.
 
Okay I mapped sinx and got:
2sin^{2}x-3sinx+sinx=0
(2sinx-1)(sinx-1)=0
2sinx=1 or sinx=1
sinx=1/2

Is this correct?
 
You should learn to check your answers. Let's test it, if sinx=1/2 then the equation becomes:

2*1/4-3*1/2+1/2=-1/2!=0

So no it is not right.
 
Last edited:
But x=30 or x=90
then,
substitute in the original equation of 2sinx + cosecx and you get the R.T.P answer of 3.
 
Okay I mapped sinx and got:
2sin^{2}x-3sinx+sinx=0
(2sinx-1)(sinx-1)=0
2sinx=1 or sinx=1
sinx=1/2p

I see what happened now. You meant to write 2sin^{2}x-3sinx+1=0 instead of 2sin^{2}x-3sinx+sinx=0. I checked your answer continuing from your first equation, which is wrong. All other steps are correct and your answers satisfy the original equation.
 
Thanks for helping
 
DERRAN said:
Thanks for helping

Just remember that you were asked to give the general solution and not just solve in a given range.
 

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