Matrix A s.t. A^3=0 but A^2 doesn't

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Homework Help Overview

The discussion revolves around finding a matrix A such that A cubed equals zero (A3 = 0) while A squared does not equal zero (A2 ≠ 0). This topic falls within the subject area of linear algebra, specifically focusing on properties of nilpotent matrices.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants express skepticism about the possibility of such a matrix existing. Some suggest considering a 3x3 matrix with specific properties, while others reflect on the implications of matrix multiplication and the structure of nilpotent matrices.

Discussion Status

The discussion is ongoing, with participants exploring different ideas and questioning their understanding of matrix properties. There are suggestions to investigate specific matrix forms and references to relevant theorems, indicating a productive exploration of the topic.

Contextual Notes

Participants mention the need to work with n x n matrices and reference theorems related to nilpotent matrices, highlighting constraints in their reasoning and the assumptions they are considering.

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Homework Statement


Find a matrix, A, such that A3=0, but A2≠0.


Homework Equations





The Attempt at a Solution


I don't actually think this is possible. My only other thought is to take A2*A where this product equals zero, and then decompose A. But I don't know how to do that such that it is the "square root" of A.
 
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NullSpace0 said:

Homework Statement


Find a matrix, A, such that A3=0, but A2≠0.


Homework Equations





The Attempt at a Solution


I don't actually think this is possible. My only other thought is to take A2*A where this product equals zero, and then decompose A. But I don't know how to do that such that it is the "square root" of A.

Try a 3x3 matrix with 1s above the diagonal.
 
How would I have known to look for that?

From what I know about matrix multiplication, I know that the zeroes below the diagonal help when I think of multiplying by taking linear combinations of the columns, but how would I reason this out in general?
 
NullSpace0 said:
How would I have known to look for that?

From what I know about matrix multiplication, I know that the zeroes below the diagonal help when I think of multiplying by taking linear combinations of the columns, but how would I reason this out in general?

Let A be an n xn matrix for which A^k = 0 for some k > n. Prove that A^n = 0.

This theorem tells me to work on nxn matrices since I know I know I can construct one that is A^n = 0. So your case we needed A^3. Hence I picked a 3x3
 
NullSpace0 said:
How would I have known to look for that?

From what I know about matrix multiplication, I know that the zeroes below the diagonal help when I think of multiplying by taking linear combinations of the columns, but how would I reason this out in general?

Re "How would I have known to look for that?" I'll bet your book or notes have some relevant material. Alternatively, you could Google 'nilpotent matrix', but I guess you would need to know that is what such A are called.

RGV
 

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