General Relativity math, Tangent vectors on manifolds

Click For Summary
SUMMARY

This discussion focuses on the mathematical concepts of tangent vectors on manifolds within the context of differential geometry and general relativity. The participants clarify that the variable yi(t) represents components of a single path on the manifold, while yj denotes the ambient coordinates of the manifold. They emphasize that a smooth path is a mapping from a line segment in R to points on the manifold, requiring N-1 equations to define a curve. Additionally, they address the relationship between ambient and local coordinates, specifically the use of indices in the context of the Kronecker delta.

PREREQUISITES
  • Differential Geometry fundamentals
  • Understanding of Manifolds and their properties
  • Knowledge of Smooth Functions and mappings
  • Familiarity with Kronecker delta notation
NEXT STEPS
  • Study the concept of Smooth Manifolds in detail
  • Learn about the relationship between Ambient and Local Coordinates
  • Explore the definition and applications of the Kronecker Delta in differential geometry
  • Investigate the mathematical formulation of curves on manifolds
USEFUL FOR

Students and researchers in mathematics, particularly those studying differential geometry, general relativity, and the mathematical foundations of physics.

Domisterwoozy
Messages
6
Reaction score
0
I am currently going through some online notes on differential geometry and general relativity. So far I have been following pretty well until I got to 3.4 cont'd letter (e) of http://people.hofstra.edu/Stefan_Waner/diff_geom/Sec3.html" document and the definition directly after. My first question is, is yi(t) many different paths on the manifold or is each i a component of one path on the manifold? Also in the definition after the example I think yj are the ambient components of the actual manifold, not the path, and xi are the local components of the manifold, not the path. Is this correct? And if so how do you take the partials if the number of components of the ambient coordinates are usually one more then the number of components of the local coordinates?

If my questions do not make sense, just ask and I will try to make them more clear, and if this is not the right place for this just direct me where to go. Also if anyone had any better suggestions on places to learn this stuff I am happy to hear it.
 
Last edited by a moderator:
Physics news on Phys.org
Domisterwoozy said:
I am currently going through some online notes on differential geometry and general relativity. So far I have been following pretty well until I got to 3.4 cont'd letter (e) of http://people.hofstra.edu/Stefan_Waner/diff_geom/Sec3.html" document and the definition directly after. My first question is, is yi(t) many different paths on the manifold or is each i a component of one path on the manifold?
The later, it's one path.

Also in the definition after the example I think yj are the ambient components of the actual manifold, not the path,

I'm not following this. The yj are just coordinates. A complete set of coordinates specifies a point on the manifold, just like it does on a map. Though a purist would note that a point is different from the coordinates that specify it.

I suspect you're confused somehow about the first definition, but I can't quite grasp how you're confused, so maybe I'm wrong and I'm confused. Anyway...

In loose language, the first definition just says that a smooth path is just a mapping from a line segment on R to a set of points on the mainfold (I'd call it a curve on the manifold, but that's sort of what we're trying to define), such that every point on the line corresponds to one point on the manifold, said point specified by its coordinates, yj, and the mapping is "smooth". They haven't gotten into the details of "smoothness" in the notes, so I won't get into it either.
 
Last edited by a moderator:
Any point on the N-dimensional manifold is specified by N coordinates {x1...xN}.

Roughly, to specify a curve, which is 1-dimensional, we need N-1 equations to "get rid" of N dimensions. These are the N equations {x1=f1(t) ... xN=fN(t)}, which we think of as N-1 equations by notionally eliminate t to obtain N-1 relations among N coordinates.

As an explicit example, in 2D with coordinates {x,y} a circle can be written as {x=cost,y=sint} or x2+y2=1.

Semantic note: many define a curve to be a parametrized path so that {x=cost,y=sint} is a curve, but x2+y2=1 is a path.
 
Last edited:
Thanks for the reply.

I am pretty sure I understand the basic definition of a path. Where I am running into trouble is I thought that the ambient coordinates consist of s coordinates and the local coordinates consist of n coordinates where s = n +1. Basically the manifold is embedded into a one higher dimension. However, in that example (e) they assign xj based off of if i = j, however I thought that j > i since there are more y coordinates then x coordinates. Therefore how can you compare the two and make a Kronecker delta which I thought was supposed to be a square matrix.
 
Domisterwoozy said:
Thanks for the reply.

I am pretty sure I understand the basic definition of a path. Where I am running into trouble is I thought that the ambient coordinates consist of s coordinates and the local coordinates consist of n coordinates where s = n +1. Basically the manifold is embedded into a one higher dimension. However, in that example (e) they assign xj based off of if i = j, however I thought that j > i since there are more y coordinates then x coordinates. Therefore how can you compare the two and make a Kronecker delta which I thought was supposed to be a square matrix.

i,j are just indices which he uses for both local and ambient coordinates, so whether they run from 1...n or 1...s depends on whether local or ambient coordinates are being indexed (I think). So in 3.4e the Kronecker delta indices run from 1...n, the dimension of the manifold, not the ambient space.
 
Last edited:

Similar threads

  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 76 ·
3
Replies
76
Views
4K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 63 ·
3
Replies
63
Views
5K
  • · Replies 83 ·
3
Replies
83
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K