General Solution for y''-18y'+80y=0 w/ Variable t

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SUMMARY

The general solution to the differential equation y'' - 18y' + 80y = 0 is expressed as y(t) = Ce2t + De3t, where C and D are arbitrary constants. This solution encompasses all possible functions that satisfy the equation, meaning any function of the form Ce2t + De3t is a valid solution. The variable t represents the independent variable with respect to which y is defined, and the general solution characterizes every solution to the differential equation.

PREREQUISITES
  • Understanding of differential equations, specifically second-order linear homogeneous equations.
  • Familiarity with the concepts of derivatives and functions of a variable.
  • Knowledge of arbitrary constants in mathematical solutions.
  • Basic algebraic manipulation skills to verify solutions.
NEXT STEPS
  • Study the method of characteristic equations for solving linear differential equations.
  • Learn about the implications of arbitrary constants in general solutions.
  • Explore the concept of linear independence of solutions in differential equations.
  • Investigate the application of differential equations in real-world scenarios.
USEFUL FOR

Students of mathematics, particularly those studying differential equations, educators teaching these concepts, and anyone interested in mathematical modeling using differential equations.

beanryu
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Here is my question

Find the general solution to the differential equation

y''-18y'+80y=0

Express the solution in terms of the variable t. Give the smaller root first.

My problem is that I don't know what general solution mean?
what does it mean?

And where does the t come from?
 
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Example:

y'' - 5y' + 6y = 0

So you want to find all functions y that satisfy this equation. If we say that y is a function of t, then y' denotes the derivative of y with respect to t. There's nothing special about t, however. A function y has to be a function of some variable. We could have very well called our variable, say, x. Then y' would denote the derivative of y with respect to x. Now the general solution to the differential equation I gave is:

y(t) = Ce2t + De3t

But here y depends not only on t, but also on C and D, so it might be better to write:

yC,D(t) = Ce2t + De3t

What does it mean for yC,D to be the general solution? It means two things:

1) for any choice of real numbers C and D, the resulting function is a solution to the differential equation. For example, the following two different functions:

y7,12.9921(t) = 7e2t + 12.9921e3t
y0,1(t) = e3t

are both solutions to the differential equation. In order to check this, compute y7,12.9921', y7,12.9921'', and y0,1', y0,1''. Plug these into the differential equation, and see that in both cases, the left side really does end up being 0.

Again, the above is only two possible choices for the pair C,D. Any imaginable choice will do (normally, you restrict your choice of C and D to real numbers, but you could even choose complex numbers, quaternions, whatever!)

2) Every function which solves this differential equation is in the form Ce2t + De3t. That is, if f is some function of t, and there are no number C and D such that

f(t) = Ce2t + De3t

Then f can not be a solution to the differential equation. In other words, you will get every possible solution to the differential equation if you consider every possible choice of C and D in the general solution yC,D(t) = Ce2t + De3t. That is y is called the general solution, because it characterizes every solution.

You must already have been taught how to find the general solution to such a differential equation.
 

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