I'm doing some work on schwarzchild orbits, and everything assumes that [tex]\theta=\pi/2[/tex] and claims that this doesn't compromise generality. It seems pretty obvious (since all the geodesics are planar or radial and the metric is spherically symmetric), but can anyone prove that [tex]\theta=\pi/2[/tex] is fully general?(adsbygoogle = window.adsbygoogle || []).push({});

here's the metric if you need it:

[tex]ds^2=fdt^2-(1/f)dr^2+r^2d\Omega^2[/tex]

where

[tex]f=1-(2m/r)[/tex]

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# Generality of theta=pi/2 in Schwarzchild

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