Generalization of hypergeometric type differential equation

  • #1
15
1

Main Question or Discussion Point

I am aware that hypergeometric type differential equations of the type:

upload_2018-6-18_19-12-53.png


can be solved e.g. by means of Mellin transforms when σ(s) is at most a 2nd-degree polynomial and τ(s) is at most 1st-degree, and λ is a constant. I'm trying to reproduce the method for the case where λ is not constant, but a 3rd-degree polynomial, and I'm not sure how to solve Mellin-transformed version of the equation above if λ is a polynomial and not a constant, if indeed it is solvable analytically.

Does the equation above have analytical solutions if λ(s) is a 3rd-degree polynomial, and if so, how do I arrive at them?
 

Attachments

Answers and Replies

  • #2
Paul Colby
Gold Member
1,034
230
I played around with equations "similar" to these in graduate school. I would just point out (forgive if this is obvious) if ##\sigma(s)## and ##\tau(s)## are restricted to polynomials of second and first order then the equation viewed as an operator on ##y(s)## sends polynomials of order ##n## into polynomials of order ##n## which I believe is what makes them "special". Letting ##\lambda## be a polynomial in ##s## will break this property.
 

Related Threads on Generalization of hypergeometric type differential equation

  • Last Post
Replies
1
Views
1K
Replies
7
Views
4K
Replies
1
Views
2K
  • Last Post
Replies
2
Views
2K
Replies
7
Views
2K
Replies
5
Views
2K
Replies
3
Views
2K
Replies
2
Views
2K
  • Last Post
Replies
0
Views
2K
Replies
5
Views
1K
Top