- #1
Pere Callahan
- 586
- 1
Hello this is something that just crossed my mind:
For every real sequence [itex](a_n)_{n\geq 1}[/itex] we can define the generating function
[tex]
A(z)=\sum_{n=1}^\infty{a_nz^n}.
[/tex]
and this definition suggests that we can compute the sum of the sequence by evaluating A at 1:
[tex]
A(1)=\sum_{n=1}^\infty{a_n}
[/tex]
provided the sum converges.
This made me wonder if for any sequence of weights [itex](w_n)_{n\geq 1}[/itex] there is a real number x such that we can compute the sum
[tex]
\sum_{n=1}^\infty{w_na_n}
[/tex]
as A(x).
I haven't spent much time on this, but I would be very interested in any thoughts on the topic.
Thanks,
Pere
For every real sequence [itex](a_n)_{n\geq 1}[/itex] we can define the generating function
[tex]
A(z)=\sum_{n=1}^\infty{a_nz^n}.
[/tex]
and this definition suggests that we can compute the sum of the sequence by evaluating A at 1:
[tex]
A(1)=\sum_{n=1}^\infty{a_n}
[/tex]
provided the sum converges.
This made me wonder if for any sequence of weights [itex](w_n)_{n\geq 1}[/itex] there is a real number x such that we can compute the sum
[tex]
\sum_{n=1}^\infty{w_na_n}
[/tex]
as A(x).
I haven't spent much time on this, but I would be very interested in any thoughts on the topic.
Thanks,
Pere