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## Homework Statement

An experiment consistion of tossing three fair coins is performed repeatedly and "success" is when all three show a head.

What is the probability that the success is on the third performance of the experiment?

## Homework Equations

Geometric distribution equation

p(x) = [tex]\theta[/tex](1-[tex]\theta[/tex])[tex]\stackrel{(x-1)}{}[/tex]

where [tex]\theta[/tex] is the probability of success

## The Attempt at a Solution

The probability of getting heads on a fair coin is 1/2

so the probability of 3 heads is 1/8 which is [tex]\theta[/tex]

I'm assuming the third trial is when x=3 so

p(3) = (1/8)*(1-(1/8))^2

p(3) = 0.095703125...

Am I correct in my working/method for this question?

Many thanks

James