Geometric Distribution Question

  • Thread starter James...
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Homework Statement



An experiment consistion of tossing three fair coins is performed repeatedly and "success" is when all three show a head.

What is the probability that the success is on the third performance of the experiment?



Homework Equations



Geometric distribution equation

p(x) = [tex]\theta[/tex](1-[tex]\theta[/tex])[tex]\stackrel{(x-1)}{}[/tex]

where [tex]\theta[/tex] is the probability of success


The Attempt at a Solution



The probability of getting heads on a fair coin is 1/2

so the probability of 3 heads is 1/8 which is [tex]\theta[/tex]

I'm assuming the third trial is when x=3 so

p(3) = (1/8)*(1-(1/8))^2

p(3) = 0.095703125...


Am I correct in my working/method for this question?

Many thanks

James
 

Answers and Replies

  • #2
CompuChip
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Looks fine to me!
 
  • #3
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Cheers! I know the actualy calculation is done right. Just wasn't completly sure if I'd used the right method.

I stupidly left the notes I did for the question at University and I'm revising now at home so can't check over them.
 

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