- #1

Augustine Duran

- 39

- 1

## Homework Statement

A person with a near point of

**100 cm**, but excellent distant vision, normally wears corrective glasses. But he loses them while traveling. Fortunately, he has his old pair as a spare. If the lenses of the old pair have a power of

**+2.55 diopters**, what is his near point (measured from his eye) when he is wearing the old glasses if they rest

**2.00 cm**in front of his eye?

## Homework Equations

[/B]

1/f = 1/s + 1/s'

## The Attempt at a Solution

[/B]

im having trouble figuring out what's the image distance and object distance. I am assuming his original near point (

**100cm**) is the image distance. If i plug in

**-98cm**(subtracting the

**2.0 cm**from his eye) and

**39.2**as the focal length that means ill be solving for S, which is confusing me since s is for object distance yet there's no object? wouldn't his new near point also be an image distance?