Geometry problem involving dot/cross product

  • Thread starter Thread starter hanelliot
  • Start date Start date
  • Tags Tags
    Geometry Product
Click For Summary

Homework Help Overview

The problem involves a line and a plane defined by specific vector equations, with a condition on the dot product of a direction vector and the cross product of two other vectors. The goal is to demonstrate the relationship between the line and the plane based on this condition.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of the dot product being zero, indicating perpendicularity, and explore whether the line intersects the plane at the zero vector or lies within it. Some suggest considering cases based on the position of a point on the line relative to the plane.

Discussion Status

Participants are engaging with the problem by examining different scenarios and questioning the validity of their reasoning. Some have offered guidance on how to approach the proof by considering specific cases related to the position of points on the line and plane.

Contextual Notes

There is a focus on the geometric interpretation of the problem, with some participants expressing uncertainty about the formal proof process and whether their intuitive understanding is sufficient.

hanelliot
Messages
18
Reaction score
0

Homework Statement


Let r be a line and pi be a plane with equations
r: P + tv
pi: Q + hu + kw (v, u, w are vectors)
Assume v · (u x w) = 0. Show that either r ∩ pi = zero vector or r belongs to pi.

Homework Equations


n/a


The Attempt at a Solution


I get the basic idea behind it but I'm not sure if my "solution" is formally good enough. I know that cross product gives you a normal to a plane, which is u x w here. I also know that the dot product = 0 means that they are perpendicular to each other.. so v and (u x w) are perpendicular to each other. If you draw it out, you can clearly see that r must be either in pi or out of pi. Is this good enough to warrant a good mark? Thanks!
 
Physics news on Phys.org
hanelliot said:

Homework Statement


Let r be a line and pi be a plane with equations
r: P + tv
pi: Q + hu + kw (v, u, w are vectors)
Assume v · (u x w) = 0. Show that either r ∩ pi = zero vector or r belongs to pi.
if r is parallel to pi, but not "in" pi their intersection will not be the zero vector, it will be the empty set

hanelliot said:
[

The Attempt at a Solution


I get the basic idea behind it but I'm not sure if my "solution" is formally good enough. I know that cross product gives you a normal to a plane, which is u x w here. I also know that the dot product = 0 means that they are perpendicular to each other.. so v and (u x w) are perpendicular to each other. If you draw it out, you can clearly see that r must be either in pi or out of pi. Is this good enough to warrant a good mark? Thanks!

Homework Statement


try the separate cases when P is "in" pi, and when P is not "in" pi and try and see if you can show whether any arbitrary point on r is in, or not in P, knowing that v = a.(uXw) where a is some non-zero constant
 
lanedance said:
if r is parallel to pi, but not "in" pi their intersection will not be the zero vector, it will be the empty set
you are right, my mistake


try the separate cases when P is "in" pi, and when P is not "in" pi and try and see if you can show whether any arbitrary point on r is in, or not in P, knowing that v = a.(uXw) where a is some non-zero constant
I can show that with intuition and a sketch of plane/line but not sure how I should go about proving it formally.. maybe this Q is that simple and I'm overreacting
 
as you know
v.(u x w) = 0

then
v = au + bw
for constants a & b - why?

equation of you line is P + vt

now, i haven't tried, but using your equation of a line & the equation of a plane, considering the following cases, should show what you want:

Case 1 - P is a point in pi. Now show any other point on the line, using the line equation, satisfies the equation defining pi.

Case 2 - P is not a point in pi. Now show any other point on the line, using the line equation, does not satisfy the equation defining pi.
 

Similar threads

Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
6
Views
2K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K